将输出重定向到命令结果给定的文件名 [英] Redirect output to filename given by result of command

问题描述

假设我有一种文件格式，希望将数据库备份保存为给定的格式:

Suppose I have a file format I want to save database backups to given as such:

echo "~/backups/$(date +'%Y-%m-%d_%H-%M-%S').sql"

现在如何将这个结果指定为文件名，以便在Shell中输出?

Now how can I specify this result as a filename for output in shell?

mysqldump my_db > ....?

顺便说一句: shell将嵌套的echo命令的结果解释为可执行的命令/文件.所以   似乎是:

By the way: shell interprets the result of a nested echo command as an executable command/file. So    It would seem that:

 mysqldump my_db > $(echo "something")

不起作用.相反，shell查找名为 something 的文件并尝试执行该文件?

does NOT work. Instead, shell looks for a file called something and tries executing it?

推荐答案

无需使用嵌套回显.您可以避免它:

There is no need to use nested echo. You can avoid it:

mysqldump my_db > ~/backups/$(date +'%Y-%m-%d_%H-%M-%S').sql

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