您可以在陷阱中访问退出命令的代码吗? [英] Can you access the code of an exit command in a trap?

问题描述

我知道我可以使用$?来查看最后执行的命令的退出代码，但是如果我想确定自己抛出了自己的退出0"还是退出1"怎么办?

例如:

 #！/bin/bash -e陷阱"{echo退出代码$ ?;退出;}"退出1号出口 

如果运行此脚本，它将打印出退出代码0"，然后以退出代码1退出.我可以访问陷阱中的代码吗，还是我使用错误的方法?换句话说，我希望这个简单的脚本打印出退出代码1".

解决方案

为0，因为脚本开头的 $?(由于双引号而被替换)为0./p>

尝试以下方法:

  trap'{echo退出代码$ ?;出口;}' 出口 

I understand that I can use $? to see the exit code of the last executed command, but what if I want to identify whether I have thrown my own "exit 0" or "exit 1"?

For example:

#!/bin/bash -e    
trap "{ echo Exit code $?; exit; }" EXIT    
exit 1

If I run this script, it prints out "Exit code 0" and then exits with exit code 1. Can I access the code in the trap, or am I just going about this the wrong way? In other words, I would like this simple script to print out "Exit code 1".

解决方案

It's 0 because $? at the beginning of a script, where it is substituted due to the double quotes, is 0.

Try this instead:

trap '{ echo Exit code $?; exit; }' EXIT

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