使用bash仅提取传入电子邮件的正文部分 [英] Extract only the body part of incoming emails using bash

问题描述

我使用 offlineimap 将邮件提取到Maildir文件夹中.

I use offlineimap to fetch the mails into a Maildir folder.

我想自动解析Maildir文件夹中的所有新收到的电子邮件，并仅在其他位置发送发件人"，主题"和正文"作为即时消息.

I want to automatically parse all new incoming emails in a Maildir folder and send only the "from", "subject" and "body" as an instant message somewhere else.

所以我尝试处理所有邮件

So I try to process all mails with

MPATH=~/Mail 

if [ -n "$(ls "$MPATH/INBOX/new/")" ]; then 
    for f in "$MPATH/INBOX/new/"*; do  
        SUB="$(cat "$f"|grep '^Subject' | head -n1 | sed "s/Subject: //g")"                                                                                       
        FROM="$(cat "$f" | grep '^From' | head -n1 | head -n 1|sed "s/From: //g")"                                                                                
        BODY="$(cat "$f"|sed -e '1,/Content-Transfer-Encoding/d')"
        MESS="$FROM: $SUB$BODY"

        echo $f 
        echo "$MESS" 
        mv "$f" "$MPATH/INBOX/cur/" 
    done 
fi

这对于某些简单的电子邮件来说已经可以正常工作，但是我如何摆脱不简单的内容，例如签名，附件等?

This already works fine for some simple emails, but how do I get rid of everything that is not the plain body, like signatures, attachements,...?

推荐答案

如formail联机帮助页上所建议的那样，对我有用:

As suggested on formail manpage, that worked for me:

cat mailfile | sed -e '1,/^$/ d' 

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