我想在另一个字符串模式前面找到一些字符串，该怎么办? [英] I want to find some string in front of another string pattern, how to do it?

问题描述

我想使用bash shell分割字符串，例如:

I want to use bash shell to split string like:

Calcipotriol - Daivonex Cream 50mcg/1g 30 g [1]
Aspirin - DBL Aspirin 100mg [1] tablet

我想获得商标名称"Davionex Cream"和"DBL Aspirin"我想把名字放在*** mg或*** mcg或*** g前面

I want to get brand name "Davionex Cream" and "DBL Aspirin" I want to get the name in front of parttern ***mg or ***mcg or ***g

该怎么做?

推荐答案

在Bash中，您可以执行以下操作:

In Bash you can do:

while IFS= read -r line || [[ -n "$line" ]]; do
    if [[ "$line" =~ ^([[:alpha:]]+)[[:space:][:punct:]]+([[:alpha:][:space:]]+)[[:space:]](.*)$ ]]
    then
         printf "1:'%s' 2:'%s' 3:'%s'\n" "${BASH_REMATCH[1]}" "${BASH_REMATCH[2]}" "${BASH_REMATCH[3]}"
    fi  
    done <<<"Calcipotriol - Daivonex Cream 50mcg/1g 30 g [1]
Aspirin - DBL Aspirin 100mg [1] tablet" 

打印:

1:'Calcipotriol' 2:'Daivonex Cream' 3:'50mcg/1g 30 g [1]'
1:'Aspirin' 2:'DBL Aspirin' 3:'100mg [1] tablet'

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