bash-从远程ssh命令捕获退出代码 [英] bash - Capture exit code from remote ssh command

问题描述

我正在寻找在shell脚本中捕获远程ssh命令的退出状态我有一个如下的shell脚本:

I'm looking at capturing the exit status of a remote ssh command within a shell script I have a shell script as follows :

function rSSH {
   local x
   echo "Running ssh command"
   x=$(ssh -o StrictHostKeyChecking=no -i $keyPair -o ProxyCommand="ssh -W %h:%p -i $keyPair user@$bastionIP 22" user@$IP "$cmd")

   x=$?
   echo "SSH status is : $x"
   if [ $x -eq 0 ];then
      echo "Success"

   else
      echo "Failure"
      exit 1
   fi
}

rSSH
exit 0

当我使用无效的$ bastionIP(测试失败方案)将上述脚本作为后台作业执行时，其结果是退出代码为0(而不是1)，并且我在日志中看到的唯一信息是第一个回显正在运行ssh命令"，它只是退出脚本.

When I execute the above script as a background job with an invalid $bastionIP( testing failure scenario), it results with an exit code of 0 ( instead of 1) and the only information I see in the logs is the first echo "Running ssh command" and it just exits the script.

有人可以指出我做错了什么还是捕获远程ssh命令退出状态的更好方法.感谢任何帮助.

Can someone point out what I'm doing wrong or a better way to capture the exit status of the remote ssh command. Appreciate any help.

推荐答案

该脚本似乎正在 set -e 下运行，这意味着当 ssh 连接失败时，脚本立即退出.

The script appears to be running under set -e, which means when the ssh connection fails, the script exits immediately.

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