正则表达式允许字符串中的空格-bash [英] Regex to allow spaces in string - bash

问题描述

我没有带空格的字符串来验证.它可以在没有空格的情况下工作，但是当我在字符串中包含空格时，它将失败.我已经用Google搜索了，但无法正常工作.

I can't get a string with spaces to validate. It works without spaces, but when I include a space in the string it fails. I have googled furiously but can't get it to work.

if [[ $string =~ ^"[A-Za-z ]"$ ]]; then
    # true
else 
    # false
fi

我不确定我在这里缺少什么...

I'm not sure what I'm missing here...

推荐答案

使用变量存储您的正则表达式:

Use a variable to store your regex:

re='^[A-Za-z ]+$'

然后将其用作:

[[ "string" =~ $re ]] && echo "matched" || echo "nope"
matched

[[ "string with spaces" =~ $re ]] && echo "matched" || echo "nope"
matched

如果要使用内联正则表达式，请使用:

If you want inline regex then use:

[[ "string with spaces" =~ ^[A-Za-z\ ]+$ ]] && echo "matched" || echo "nope"
matched

否则使用 [[:: blank:]] 属性:

[[ "string with spaces" =~ ^[A-Za-z[:blank:]]+$ ]] && echo "matched" || echo "nope"
matched

这篇关于正则表达式允许字符串中的空格-bash的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！