生成唯一的标签以重复执行命令的结果 [英] Generate unique tags to repeating results of a command

问题描述

我正在运行一个脚本，该脚本会生成连续的输出，例如:

I have a script running which generates continuous output such as:

/AtherosC_92:f1:a7  BTHub4-NJ8S -82
/AtherosC_92:f1:a7  BTHub4-NJ8S -81
/95:8c:ed:6d:65:f5  Home245 -84
/AtherosC_92:f1:a7  BTHub4-NJ8S -78
/3d:cc:54:d1:4f:f6  BTWifi2 -82
/Apple_e5:e8:2d SKYBD80F    -71
/Apple_e5:e8:2d SKYBD80F    -71
/Apple_e5:e8:2d SKYBD80F    -72

每行包括3个部分(如上所述，字符串，字符串，整数).我需要根据每行的第一个字符串为每行分配一个唯一的标识符，并创建如下输出:

Each line is comprised of 3 sections (string, string, int as above). I need to assign each line a unique identifier based on the first string of each line, creating an output like this:

/1 AtherosC_92:f1:a7    BTHub4-NJ8S -82
/1 AtherosC_92:f1:a7    BTHub4-NJ8S -81
/2 95:8c:ed:6d:65:f5    Home245 -84
/1 AtherosC_92:f1:a7    BTHub4-NJ8S -78
/3 3d:cc:54:d1:4f:f6    BTWifi2 -82
/4 Apple_e5:e8:2d   SKYBD80F    -71
/4 Apple_e5:e8:2d   SKYBD80F    -71
/4 Apple_e5:e8:2d   SKYBD80F    -72

关于如何实现他的任何建议?

Any suggestions as to how his could be achieved?

推荐答案

纯Bash解决方案:

#!/bin/bash

declare -A seen
tag=0
while read; do
    read -r first _ <<< "$REPLY"
    [[ $first ]] || continue
    if [[ -z ${seen["$first"]} ]]; then
        seen["$first"]=$((++tag))
    fi
    printf '\\%d %s\n' "${seen["$first"]}" "$REPLY"
done

---

以下内容基于@rici的解决方案(谢谢！):

---

The following is based on @rici's solution (thanks!):

#!/bin/bash

declare -A seen=()
while read && read -r first _ <<< "$REPLY" ; do
    [[ $first ]] && printf '\\%d %s\n' "${seen["$first"]=$((${#seen[@]}+1))}" "$REPLY"
done

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