Bash遍历每行并使用每行的第一个单词和第二个单词运行命令 [英] Bash iterate over each line and run a command utilizing the first word and second word of each line

问题描述

我有一个解析文件的函数，并将其分解为存储在变量中的以下输出

I have a function that parses a file and got it down to the following output which is stored in a variable

option1 value1
option2 value2
option3 value3
etc...

我需要遍历每行并在每行上运行使用两个值的命令.以下是我的想法

I need to loop through each line and run a command that uses both values on each line. Something like the following is what I'm thinking

for each line in "$var"; do
    command "$first_word $second_word"
done

我该怎么做?

推荐答案

每 BashFAQ#1 ，而边读循环则是适合该作业的工具:

Per BashFAQ #1, a while read loop is the appropriate tool for the job:

while read -r first_word second_word rest; do
  your_command "$first_word" "$second_word"
done <<<"$var"

请注意 rest 的使用-具有占位符( _ 也很常见)意味着第二个之后的单词也不会放置在 second_word中变量.

Note the use of rest -- having a placeholder (_ is also common) means that words after the second one are not also placed in the second_word variable.

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