如何以shell依赖格式获取cwd? [英] How to get the cwd in a shell-dependend format?

问题描述

由于我同时使用Windows的 cmd.exe 和 msysgit 的 bash ，试图通过 os.getcwd()访问Windows路径输出，这导致Python尝试访问以驱动器号和冒号开头的路径，例如 C:\ ，该 bash 正确地确定了无效的unix路径，在本示例中，该路径应以/c/开头.但是，如何修改Windows路径使其成为msys 等效的iff 脚本在中运行bash ?

Since I'm using both Windows' cmd.exe and msysgit's bash, trying to access the Windows-path output by os.getcwd() is causing Python to attempt accessing a path starting with a drive letter and a colon, e.g. C:\, which bash correctly determines an invalid unix-path, which instead should start with /c/ in this example. But how can I modify a Windows-path to become its msys-equivalent iff the script is running within bash?

推荐答案

难看，但是除非您为Windows创建环境变量 SHELL = bash ，否则它应该可以工作:

Ugly but should work unless you create an environment variable SHELL=bash for Windows:

def msysfy(dirname):
    import os
    try:
        shell = os.environ['SHELL']
    except KeyError:  # by default, cmd.exe has no SHELL variable
        shell = 'win'
    if os.path.basename(shell)=='bash' and dirname[1] == ':':
        return '/' + dirname[0].lower() + '/' + dirname[2:]
        # don't worry about the other backslashes, msys handles them
    else:
        return dirname

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