批处理脚本以移动n个文件交换时间 [英] batch script to move n files exch time

问题描述

我目前有一个脚本可以将temp_dir中的所有文件移动到dir并处理文件.我想更改它以批量移动n个文件来处理它们.通过批处理脚本实现此目标的最佳方法是什么.

I currently have a script to move all files in a temp_dir to dir and process files. I would like to change it to move n files in batches to process them. What would be best way to achieve it through batch script.

推荐答案

我不太确定您需要什么.

I'm not quite sure what you need.

• 您是否打算以N批处理每个文件，直到没有剩余文件?
• 还是您打算只处理每个目录的前N个文件，而忽略其余所有文件?

您可以使用模运算来每N个循环暂停一次.模数计算除法后的余数.如果模数为0，则分子被分母平均除.它是这样的:

You could use a modulo operation to pause every N loops. A modulus calculates the remainder after a division. If the modulus is 0, then the numerator is divided evenly by the denominator. It works like this:

0 % 3 = 0
1 % 3 = 1
2 % 3 = 2
3 % 3 = 0
4 % 3 = 1
5 % 3 = 2
6 % 3 = 0

以此类推.

这是一个示例批处理脚本，它具有取模操作，可以暂停每个％filesPerChunk％循环迭代.使用 .bat 扩展名保存并尝试.

Here's an example batch script with a modulo operation to pause every %filesPerChunk% loop iterations. Save this with a .bat extension and try it out.

@echo off
setlocal enabledelayedexpansion

set /a "filesPerChunk=5, idx=0"

for /F "delims=" %%I in ('dir /s /b') do (
    echo Processing %%I

    set /a "idx+=1"
    set /a "mod=idx %% filesPerChunk"

    if !mod! equ 0 (
        echo --- END OF CHUNK ---
        pause
    )

)

---

方案2:每个目录仅处理前N个文件

这可以通过一个简单的计数器来完成，该计数器针对遇到的每个文件递增，并在遇到新目录时重置为0.

---

Scenario 2: processing only the first N files for every directory

This can be done with a simple counter that increments for each file encountered and resets to 0 when a new directory is encountered.

@echo off
setlocal enabledelayedexpansion

set filesPerChunk=5

for /F "delims=" %%I in ('dir /s /b') do (

    if "!dir!"=="%%~dpI" (
        set /a "idx+=1"
    ) else (
        if defined dir echo ---
        set idx=0
        set "dir=%%~dpI"
    )

    if !idx! lss %filesPerChunk% (
        echo Processing %%I
    )
)

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