需要使用批处理文件复制特定字符串之前的行 [英] Need to copy the lines just before a particular string using batch file

问题描述

我有一个像这样的文件:

I have a file like this:

Executing resource: D:\waste2\SPC\depks_rtl_teller_custom.spc   
Executing resource: D:\waste2\SPC\ifpks_msg_incoming_cluster.spc  
Failed to execute:   
Executing resource: D:\waste2\SQL\casapks_batch.sql  
Failed to execute:  
Executing resource: D:\waste2\SQL\depks_decbatop_kernel.sql  
Executing resource: D:\waste2\SQL\depks_services.sql  
Failed to execute:    

我需要一个批处理文件或perl脚本或ANT脚本来选择字符串"Failed to execute:"前面的所有行并将其复制到新文件.只是我需要在新文件中的失败文件列表.请协助.

I need a batch file or perl script or ANT script to pick all the lines just in front of the string "Failed to execute:" and copy to a new file. Simply the failed file list I need in a new file. Please assist.

推荐答案

使用perl，您可以执行以下操作:

With perl, you could do something like:

while(<>) {
  print $prev if /^Failed to execute:/;
  $prev = $_;
}

要直接从外壳执行，可以使用以下命令

To execute directly from your shell, you can use the following command

perl -ne 'print $prev if /^Failed to execute:/; $prev=$_' path/to/your/file

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