如何使用美丽的汤和稀土来找到包含特定文本的特定类的跨度? [英] How to find spans with a specific class containing specific text using beautiful soup and re?
问题描述
我怎么能找到所有带有'blue'类的跨度，其中包含以下格式的文本:
how can I find all span's with a class of 'blue' that contain text in the format:
04/18/13 7:29pm
因此可能是:
04/18/13 7:29pm
或:
Posted on 04/18/13 7:29pm
就构建用于执行此操作的逻辑而言，这就是我到目前为止所获得的:
in terms of constructing the logic to do this, this is what i have got so far:
new_content = original_content.find_all('span', {'class' : 'blue'}) # using beautiful soup's find_all
pattern = re.compile('<span class=\"blue\">[data in the format 04/18/13 7:29pm]</span>') # using re
for _ in new_content:
result = re.findall(pattern, _)
print result
我一直在指 https://stackoverflow.com/a/7732827 和https://stackoverflow.com/a/12229134 尝试找出实现此目的的方法，但是以上就是我到目前为止所掌握的一切.
I've been referring to https://stackoverflow.com/a/7732827 and https://stackoverflow.com/a/12229134 to try and figure out a way to do this, but the above is all i have got so far.
为弄清楚场景，跨度带有:
to clarify the scenario, there are span's with:
<span class="blue">here is a lot of text that i don't need</span>
和
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
请注意，我只需要 04/18/13 7:29 pm 即可，而无需其余内容.
and note i only need 04/18/13 7:29pm not the rest of the content.
修改2:
我也尝试过:
pattern = re.compile('<span class="blue">.*?(\d\d/\d\d/\d\d \d\d?:\d\d\w\w)</span>')
for _ in new_content:
result = re.findall(pattern, _)
print result
出现错误:
'TypeError: expected string or buffer'
推荐答案
import re
from bs4 import BeautifulSoup
html_doc = """
<html>
<body>
<span class="blue">here is a lot of text that i don't need</span>
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
<span class="blue">04/19/13 7:30pm</span>
<span class="blue">Posted on 04/20/13 10:31pm</span>
</body>
</html>
"""
# parse the html
soup = BeautifulSoup(html_doc)
# find a list of all span elements
spans = soup.find_all('span', {'class' : 'blue'})
# create a list of lines corresponding to element texts
lines = [span.get_text() for span in spans]
# collect the dates from the list of lines using regex matching groups
found_dates = []
for line in lines:
m = re.search(r'(\d{2}/\d{2}/\d{2} \d+:\d+[a|p]m)', line)
if m:
found_dates.append(m.group(1))
# print the dates we collected
for date in found_dates:
print(date)
输出:
04/18/13 7:29pm
04/19/13 7:30pm
04/20/13 10:31pm
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