如何使用BeautifulSoup在<hr class ='calibre2'&gt;之间获取内容....&lt; hr class ="calibre2"/&gt; [英] How to use BeautifulSoup to get content between&lt;hr class = &#39;calibre2&#39;&gt; ... &lt;hr class=&quot;calibre2&quot; /&gt;

问题描述

<hr class="calibre2" />
<h3 class="calibre5">-ability</h3> (in nouns 构成名词) ： <br class="calibre4" />
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ capability 能力 </span></p></blockquote>

<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ responsibility 责任 </span></p></blockquote>

<hr class="calibre2" />
<h3 class="calibre5">-ibility</h3> (in nouns 构成名词) ： <br class="calibre4" />
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ capability 能力 </span></p></blockquote>

<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ responsibility 责任 </span></p></blockquote>

<hr class="calibre2" />

这是我汤的一部分，我想在两个< hr> 之间获取内容，因为hr不是结束标记，因此我无法使用一些简单的方法，我想我是否可以使用find_next_elements，但是当他看到< hr class ='calibre2'> 时，如何让他停下来，所以我可以得到那些内容，谢谢.

above this is my part of my soup, and I want to get content between the two <hr>, because hr is not a close tag, so I couldn't use some simple method, I have think if I can use find_next_elements, but How can let him stop, when he see <hr class = 'calibre2'>, so I can get those content, thank you.

推荐答案

您可以遍历所有 hr 元素并使用

You can loop over all hr elements and use .find_next_siblings() to iterate over the next sibling elements. Then, if you meet hr, break the loop:

for hr in soup.find_all("hr", class_="calibre2"):
    for item in hr.find_next_siblings():
        if item.name == "hr":
            break

        print(item)
    print("-----")

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