对BinaryString的整数删除Java中的前导零 [英] Integer to BinaryString removes leading zero in Java

问题描述

我想将整数转换为二进制字符串.我选择使用Java允许 Integer.toBinaryString(n)的本机函数.但不幸的是，这会修剪我的输出中的前导零.例如，假设输入为 18 ，输出为 10010 ，但实际输出应该为 010010 .是否有比编写用户定义的函数更好的/将int转换为字符串的捷径?还是我在这里做错了什么?

I wanted to convert an integer to binary string. I opted to use the native function that java allows Integer.toBinaryString(n). But unfortunately, this trims the leading zero from my output. Lets say for example, I give the input as 18, it gives me output of 10010 but the actual output is supposed to be 010010. Is there a better/short-way to convert int to string than writing a user defined function? Or am I doing something wrong here?

int n = scan.nextInt();
System.out.println(Integer.toBinaryString(n));

推荐答案

它应该是 010010 ....

its suppose to be 010010....

不是真的，整数类型由32位组成，因此应该为:

not really, integer type have made up from 32 bits, so it should be:

000000000000000000000000010010 ，java不会打印该信息，在这种情况下，左零与该数字的大小无关.

000000000000000000000000010010, java is not going to print that information, left zeros are in this case not relevant for the magnitude of that number..

因此您需要自己附加前导零，因为该方法返回的字符串可以设置为以下格式:

so you need to append the leading zeros by yourself, since that method is returning a string you can format that:

String.format("%32s", Integer.toBinaryString(18)).replace(' ', '0')

或者在您的情况下使用6位

or in your case using 6 bits

String.format("%6s", Integer.toBinaryString(18)).replace(' ', '0')

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