如何将5位十进制值表示为24位值? [英] How to represent a 5 digit decimal value as a 24 bit value?

问题描述

我正在尝试转换5位数的十进制值(范围从00001到99999)，并以某种方式将其表示为拆分为3个字节的24位值，但是尝试了我知道的每种转换和移位策略，但一直陷于困境:/

I'm trying to convert a 5 digit decimal value (ranging from 00001 to 99999) and somehow represent it as a 24-bit value split into 3 bytes but have tried every conversion and bitshift tactic I know, but keep getting stuck :/

示例:十进制值为12345，我需要发送3个十六进制值[aa] [bb] [cc]，其中包括:

Example: decimal value is 12345, and I need to send 3 hex values [aa][bb][cc], which would consist of:

[aa]-最低有效|[bb]-中|[cc]-最重要

[aa] - least significant | [bb] - middle | [cc] - most significant

我希望我不会烦恼，并且有一个简单的答案，在此先谢谢您！

I'm hoping I'm not in over my head and that there is a simple answer, thanks in advance!

推荐答案

尝试以下操作:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            Decimal number = new Decimal() { number = 12345 };
            string output = number.ToString();
        }
    }
    public class Decimal
    {
        public int number { get; set; }
        public override string ToString()
        {
            string output = string.Format("[{0}][{1}][{2}]",
                (number & 0xFF).ToString("X2"),
                ((number >> 8) & 0xFF).ToString("X2"),
                ((number >> 16) & 0xFF).ToString("X2"));
            return output;
        }
    }
}

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