在Python中将数字循环移位(或旋转)数字 [英] Circularly shifting (or rotating) the digits the digits of a number in Python

问题描述

假设我有以下输入内容:

Suppose I have the following input:

1234

如何获得以下输出?

3412

这是通过将输入的数字循环移位(或旋转)两次来获得的.

This is obtained by circularly shifting (or rotating) the digits of the input twice.

我尝试了以下代码:

number = 1234
bin(number >> 1)

但是它没有产生我所期望的结果.

but it is not producing the results I was expecting.

推荐答案

>> 运算符执行它将 1234 的二进制表示形式向右移动，丢弃最右边的(最低有效)位.

It moves the binary representation of 1234 on place to the right, discarding the rightmost (least significant) bit.

因此，您的代码不会产生 3412 .

Therefore you code does not result in 3412.

您可能希望改为旋转字符串:

You probably want string rotation instead:

>>> def rotr(string, n):
...     return string[n:] + string[:n]
... 
>>> rotr("1234", 2)
'3412'

您还可以随后将其转换回整数

You can also convert it back to an integer afterwards

>>> int('3412')
3412

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