不使用加法运算符将两个数相加 [英] Adding two numbers without using the addition operator

问题描述

在c〜中为1的补码运算符.这等效于:〜a = -b +1因此，a-〜b -1= a-(-b + 1)+1= a + b – 1 + 1= a + b

In c ~ is 1's complement operator. This is equivalent to: ~a = -b + 1 So, a - ~b -1 = a-(-b + 1) + 1 = a + b – 1 + 1 = a + b

有人可以向我解释吗?

推荐答案

从我们知道的小学数学开始

From elementary school math we know

a = -(-a);

从二进制补码我们知道

-a = (~a) + 1  (invert and add one)

所以我们知道

a + b 
= a - (-b)      elementary math
= a - (~b + 1)  twos complement
= a - (~b) - 1   distribute the negative (elementary math)

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