Python成语获得与多次调用os.path.dirname相同的结果? [英] Python idiom to get same result as calling os.path.dirname multiple times?

问题描述

我发现自己需要在源树中获取python文件的父目录，该源树是多个具有一定规律性的目录.不得不多次调用dirname很麻烦.

I find myself needing to get a parent directory of a python file in a source tree that is multiple directories up with some regularity. Having to call dirname many times is clunky.

我环顾四周，很惊讶地没有找到关于此的帖子.

I looked around and was surprised to not find posts on this.

一般情况是:

import os.path as op
third_degree_parent = op.dirname(op.dirname(op.dirname(op.realpath(__file__))))

是否有更惯用的方式来执行此操作，而无需嵌套的目录名调用?

Is there a more idiomatic way to do this that doesn't require nested dirname calls?

推荐答案

归一化相对路径； os.pardir 是父级目录，根据需要重复多次.也可以通过 os.path.pardir 来获得:

Normalize a relative path; os.pardir is the parent directory, repeat it as many times as needed. It is available via os.path.pardir too:

import os.path as op

op.abspath(op.join(__file__, op.pardir, op.pardir, op.pardir))

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