Pygame中按钮内的进度条 [英] Progress bar inside a button in Pygame
问题描述
所需的行为是:
当用户将鼠标置于按钮上时,将出现深灰色进度条,并开始以恒定的速度递增.我希望能够确定完全填满需要多长时间(例如2秒).如果在进度条达到100%之前将鼠标移出按钮,则进度条应直接变为0%.如果指示条达到100%,则程序应在终端上打印一些内容.
When user hold the mouse on the button, the dark gray progress bar appears and starts to get incremented at a constant pace. I want to be able to determine how long it will take for it to completely fill (like 2 seconds). If the mouse move out the button BEFORE the progress bar has reached 100%, the progress bar should go straight to 0%. If the bar reaches 100%, the program should print something in the terminal.
这是代码:
import sys
import pygame
import time
from pygame.locals import *
from os import path
pygame.init()
screen = pygame.display.set_mode((900, int(900 * (16 / 9))))
clock = pygame.time.Clock()
BLACK = (0, 0, 0)
GREEN = (0, 255, 0)
WHITE = (255, 255, 255)
BACKGROUND_COLOR = (237, 225, 192)
LIGHT_GRAY = (60, 60, 60)
GRAY = (30, 30, 30)
class Button:
def __init__(self, screen, x, y, w, h, button_color_active, button_color_inactive, text, font, size = 50, text_color = BLACK):
self.screen = screen
self.game_folder = path.dirname(__file__)
self.font = path.join(self.game_folder, font + '.ttf')
self.x, self.y, self.w, self.h = x, y, w, h
self.button_color_active = button_color_active
self.button_color_inactive = button_color_inactive
self.text, self.size = text, size
self.text_color = text_color
self.button_rect = pygame.Rect(self.x, self.y, self.w, self.h)
self.button_font = pygame.font.Font(self.font, self.size)
self.label = self.button_font.render(self.text, 1, self.text_color)
def draw(self):
if self.button_rect.collidepoint(pygame.mouse.get_pos()):
#pygame.draw.rect(self.screen, self.button_color_inactive, self.button_rect)
for progress in range(42):
pygame.draw.rect(screen, LIGHT_GRAY, pygame.Rect(50,600,10*progress,80))
pygame.display.update()
else:
pygame.draw.rect(self.screen, self.button_color_active, self.button_rect)
self.screen.blit(self.label, (self.x + 20, self.y + 5))
def is_clicked(self, mouse_pos):
return bool(self.button_rect.collidepoint(mouse_pos))
def set_new_color(self, active_color, inactive_color):
self.button_color_active = active_color
self.button_color_inactive = inactive_color
button_start = Button(screen, 50, 600, 400, 80, GRAY, LIGHT_GRAY, 'START', 'roboto-black', 50, WHITE)
while True:
screen.fill(BACKGROUND_COLOR)
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
#pygame.draw.rect(screen, GRAY, pygame.Rect(50,600,400,80))
#pygame.draw.rect(screen, LIGHT_GRAY, pygame.Rect(50,600,10*progress,80))
button_start.draw()
pygame.display.flip()
clock.tick(60)
a = str(input('shomething: '))
推荐答案
首先,您需要一个计时器.您可以使用 pygame.clock.tick(fps)
返回的 dt
(增量时间)来增加 time
变量.仅当鼠标悬停在按钮上时才执行此操作,否则请重置计时器.
First you need a timer. You can use the dt
(delta time) that pygame.clock.tick(fps)
returns to increase a time
variable. Do this only if the mouse is hovering over the button, otherwise reset the timer.
要计算矩形的宽度,您可以执行以下操作(比例性):
To calculate the width of the rect you can do this (proportionality):
width = time * coefficient
这是一个最小的例子:
import pygame as pg
pg.init()
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
FONT = pg.font.Font(None, 36)
BACKGROUND_COLOR = (237, 225, 192)
LIGHT_GRAY = (120, 120, 120)
GRAY = (30, 30, 30)
# Button variables.
button_rect = pg.Rect(50, 100, 200, 80)
max_width = 200 # Maximum width of the rect.
max_time = 4 # Time after which the button should be filled.
# Coefficient to calculate the width of the rect for a given time.
coefficient = max_width / max_time
time = 0
dt = 0
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
mouse_pos = pg.mouse.get_pos()
if button_rect.collidepoint(mouse_pos):
# If mouse is over the button, increase the timer.
if time < max_time: # Stop increasing if max_time is reached.
time += dt
if time >= max_time:
time = max_time
else: # If not colliding, reset the time.
time = 0
width = time * coefficient
screen.fill(BACKGROUND_COLOR)
pg.draw.rect(screen, LIGHT_GRAY, (51, 100, width, 80))
pg.draw.rect(screen, GRAY, button_rect, 2)
txt = FONT.render(str(round(time, 2)), True, GRAY)
screen.blit(txt, (20, 20))
pg.display.flip()
dt = clock.tick(60) / 1000
pg.quit()
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