如何使用两个属性对对象数组进行排序,但根据条件有条件地按排序顺序进行分组? [英] How to sort an array of objects using two properties but conditionally group in the sort order depending on a condition?
问题描述
此问题是此问题的延续.
让我们说我有一个像下面这样的数组:
Lets say I have an array like below:
const questions = [
{_id: 1, q: 'why?', group: 'no-group', date: '8', selected: false },
{_id: 2, q: 'what?', group: 'group 1', date: '6', selected: false },
{_id: 3, q: 'when?', group: 'no-group', date: '7', selected: false },
{_id: 4, q: 'where?', group: 'group 1', date: '5', selected: false },
{_id: 5, q: 'which?', group: 'group 2', date: '3', selected: false },
{_id: 6, q: 'who?', group: 'no-group', date: '0', selected: false },
{_id: 7, q: 'why not?', group: 'group 2', date: '9', selected: false },
{_id: 8, q: 'who, me?', group: 'group 1', date: '4', selected: false },
{_id: 9, q: 'where is waldo?', group: 'group 1', date: '1', selected: false },
{_id: 10, q: 'which way is up?', group: 'no-group', date: '2', selected: false },
{_id: 11, q: 'when is lunch?', group: 'group-2', date: '10', selected: false },
];
如何编写代码对其进行排序,以便按日期和组对对象进行排序.但是,如果:如果说组1出现在第二个对象中,那么以下对象应该按日期进行组1排序,直到列出所有第一组对象,除具有'no-group'的对象以外的所有其他对象都相同
作为组属性值.
How can I write code to sort it so that the objects are sorted by date and by group. But if: lets say group 1 appears as the second object, then the following objects should be group 1 sorted by date until all group one objects are listed and the same for all other objects except objects that have 'no-group'
as the group property value.
所以对于上面的数组,我应该得到如下输出:
So for the array above I should get an output like below:
[
{_id: 6, q: 'who?', group: 'no-group', date: '0', selected: false },
{_id: 9, q: 'where is waldo?', group: 'group 1', date: '1', selected: false },
{_id: 8, q: 'who, me?', group: 'group 1', date: '4', selected: false },
{_id: 4, q: 'where?', group: 'group 1', date: '5', selected: false },
{_id: 2, q: 'what?', group: 'group 1', date: '6', selected: false },
{_id: 10, q: 'which way is up?', group: 'no-group', date: '2', selected: false },
{_id: 5, q: 'which?', group: 'group 2', date: '3', selected: false },
{_id: 7, q: 'why not?', group: 'group 2', date: '9', selected: false },
{_id: 11, q: 'when is lunch?', group: 'group 2', date: '10', selected: false },
{_id: 3, q: 'when?', group: 'no-group', date: '7', selected: false },
{_id: 1, q: 'why?', group: 'no-group', date: '8', selected: false },
];
// the spacing is just for easier readability.
推荐答案
您可以按日期
进行排序,对相同的组取消对象的分组并获得一个平面数组.
You could sort by date
, group by unsing an object for same groups and get a flat array.
const
questions = [{ _id: 1, q: 'why?', group: 'no-group', date: '8', selected: false }, { _id: 2, q: 'what?', group: 'group 1', date: '6', selected: false }, { _id: 3, q: 'when?', group: 'no-group', date: '7', selected: false }, { _id: 4, q: 'where?', group: 'group 1', date: '5', selected: false }, { _id: 5, q: 'which?', group: 'group 2', date: '3', selected: false }, { _id: 6, q: 'who?', group: 'no-group', date: '0', selected: false }, { _id: 7, q: 'why not?', group: 'group 2', date: '9', selected: false }, { _id: 8, q: 'who, me?', group: 'group 1', date: '4', selected: false }, { _id: 9, q: 'where is waldo?', group: 'group 1', date: '1', selected: false }, { _id: 10, q: 'which way is up?', group: 'no-group', date: '2', selected: false }, { _id: 11, q: 'when is lunch?', group: 'group 2', date: '10', selected: false }],
result = questions
.sort((a, b) => a.date - b.date)
.map((groups => o => {
if (o.group === 'no-group') return o;
if (groups[o.group]) {
groups[o.group].push(o);
return [];
}
return groups[o.group] = [o];
})({}))
.flat();
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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