将3D numpy数组拆分为较小的3D数组 [英] Split a 3D numpy array into smaller 3D arrays
本文介绍了将3D numpy数组拆分为较小的3D数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个3D np.array
I have a 3D np.array
arr = np.array([
[ [0, 205, 25], [210, 150, 30], [0, 0, 0], [1, 2, 3], [4, 5, 6], [7, 8, 9] ],
[ [0, 255, 0], [255, 40, 0], [0, 0, 200], [7, 8, 9], [10, 11, 12], [120, 51, 58] ],
[ [0, 0, 30], [0, 40, 0], [200, 100, 20], [12, 13, 14], [15, 16, 17], [13, 78, 84], ],
[ [0, 205, 25], [210, 150, 30], [0, 0, 0], [1, 2, 3], [4, 5, 6], [7, 8, 9] ],
[ [0, 255, 0], [255, 40, 0], [0, 0, 200], [7, 8, 9], [10, 11, 12], [120, 51, 58] ],
[ [0, 0, 30], [0, 40, 0], [200, 100, 20], [12, 13, 14], [15, 16, 17], [13, 78, 84], ],
[ [0, 205, 25], [210, 150, 30], [0, 0, 0], [1, 2, 3], [4, 5, 6], [7, 8, 9] ],
[ [0, 255, 0], [255, 40, 0], [0, 0, 200], [7, 8, 9], [10, 11, 12], [120, 51, 58] ],
[ [0, 0, 30], [0, 40, 0], [200, 100, 20], [12, 13, 14], [15, 16, 17], [13, 78, 84], ],
])
我需要将其拆分为3x2x3 3D阵列
And I need to split it to 3x2x3 3D arrays
[ [0, 205, 25], [210, 150, 30], [0, 0, 0], [1, 2, 3], [4, 5, 6], [7, 8, 9] ],
[ [0, 255, 0], [255, 40, 0], [0, 0, 200], [7, 8, 9], [10, 11, 12], [120, 51, 58] ],
[ [0, 0, 30], [0, 40, 0], [200, 100, 20], [12, 13, 14], [15, 16, 17], [13, 78, 84], ],
[ [0, 205, 25], [210, 150, 30], [0, 0, 0], [1, 2, 3], [4, 5, 6], [7, 8, 9] ],
[ [0, 255, 0], [255, 40, 0], [0, 0, 200], [7, 8, 9], [10, 11, 12], [120, 51, 58] ],
[ [0, 0, 30], [0, 40, 0], [200, 100, 20], [12, 13, 14], [15, 16, 17], [13, 78, 84], ],
[ [0, 205, 25], [210, 150, 30], [0, 0, 0], [1, 2, 3], [4, 5, 6], [7, 8, 9] ],
[ [0, 255, 0], [255, 40, 0], [0, 0, 200], [7, 8, 9], [10, 11, 12], [120, 51, 58] ],
[ [0, 0, 30], [0, 40, 0], [200, 100, 20], [12, 13, 14], [15, 16, 17], [13, 78, 84], ],
使用我用空格选择的这些3D块获得4D阵列.零元素必须为
to get a 4D array with these 3D blocks I've selected by spaces. Zero element must be
[
[[0, 205, 25], [210, 150, 30]],
[[0, 255, 0], [255, 40, 0]],
[[0, 0, 30], [0, 40, 0]]
]
以此类推.
我已经阅读了这个问题，但仍然没有并不要做这件事(为什么我们需要重塑，转置和重塑，以及 transpose()中的神奇数字).我可以尝试编写自己的函数，但我想知道如何以本机的方式进行操作.
I've read this question but still don't undersatand how to do this (Why we need to reshape, transpose and reshape again and what a magical numbers in transpose()). I could try to write my own function but I want to know how to do it native way.
推荐答案
您可以重塑形状并转置它
You can reshape and transpose it
arr.reshape(3, 3, 3, 2, 3).transpose(2, 0, 1, 3, 4)
# array([[[[[ 0, 205, 25],
# [210, 150, 30]],
#
# [[ 0, 255, 0],
# [255, 40, 0]],
#
# [[ 0, 0, 30],
# [ 0, 40, 0]]],
#
#
# [[[ 0, 205, 25],
# [210, 150, 30]],
#
# [[ 0, 255, 0],
# [255, 40, 0]],
#
# [[ 0, 0, 30],
# [ 0, 40, 0]]],
#
#
# ...
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