PHP在对象数组中找到匹配的属性值 [英] PHP find matching property values in an array of objects

问题描述

我有一个自定义对象数组，我想找到具有匹配属性值的对象.

I have an array of custom objects and I want to find the objects who have matching property values.

这是我的object.php:

This is my object.php:

class game_list
{
    var $team_name;
    var $field_nr;
    var $time;

    /**
     * @return mixed
     */
    public function getTeamName()
    {
        return $this->team_name;
    }

    /**
     * @param mixed $team_name
     */
    public function setTeamName($team_name)
    {
        $this->team_name = $team_name;
    }

    /**
     * @return mixed
     */
    public function getFieldNr()
    {
        return $this->field_nr;
    }

    /**
     * @param mixed $field_nr
     */
    public function setFieldNr($field_nr)
    {
        $this->field_nr = $field_nr;
    }

    /**
     * @return mixed
     */
    public function getTime()
    {
        return $this->time;
    }

    /**
     * @param mixed $time
     */
    public function setTime($time)
    {
        $this->time = $time;
    }
}

所以我有一个数组，其中包含x个这些对象.我想找到具有相同 $ field_nr 和 $ time 值的对象.例如:

So I have an array with x number of these objects. I want to find objects which have the same $field_nr and $time values. For example:

如果我的数组中的两个对象X和Y都具有 $ field_nr = 1 和 $ time ="12:00" ，我想打印出匹配！".

If two objects on my array, X and Y, both have $field_nr = 1 and $time = "12:00" I want to print out "Match!".

这是我目前正在做的事情

This is what I am doing currently:

//getPlaySchedule returns my array($feedback) of objects
$feedback= getPlaySchedule($cup_name, $cup_year, $division);

for($x=0; $x<count($feedback); $x++){
    $time = $feedback[$x]->getTime();
    $field = $feedback[$x]->getFieldNr();
    $team = $feedback[$x]->getTeamName();

    for($y=0; $y<count($feedback); $y++){
        if($time == $feedback[$y]->getTime() && $field == $feedback[$y]->getFieldNr() && $team != $feedback[$y]->getTeamName()){

            echo 'Match!';
        }
    }
}

但是，我的解决方案会打印出匹配！"每次比赛两次.有没有更好的方法可以在我的对象数组中找到这些匹配项?

My solution, however, prints out "Match!" two times for each match. Is there a better way of finding these matches in my object array?

马库斯

推荐答案

这是因为您没有存储，检查的内容以及每次循环遍历整个数组的原因.例如，如果您有对象A，B，C，D，E，F，则首先检查A.假设A将匹配D.当您选择D时，D将匹配A.

This is because you not store, what you've checked, and every time loop through the whole array. For example, if you have object A,B,C,D,E,F, first check the A. Let say, A will match D. When you check D, D will match A.

因此，您需要将其存储到数组中，或插入一个指针，检查已经检查了哪些对象，并且在检入D时，跳过A，B，C.

So you need to store it into an array, or insert a pointer, what objects checked already, and when checkin D, skip A, B, C.

一个可能的解决方案，如果您设置一个计数器(在我的示例中为 $ z )，然后从中开始第二个循环.这样可以防止脚本再次检查您已检查的内容.代码未经测试.

A possible solution, if you set a counter, in my example $z, and start the second loop from that. This prevent the script to check again what you've already checked. Code not tested.

$z = 0;
for ($x = 0; $x < count($my_array); $x++) {
    $time = $feedback[$x]->getTime();
    $field = $feedback[$x]->getFieldNr();
    $team = $feedback[$x]->getTeamName();
    for ($y = $z; $y < count($my_array); $y++) {
        if ($time == $feedback[$y]->getTime() && $field == $feedback[$y]->getFieldNr() && $team != $feedback[$y]->getTeamName()) {
            echo 'Match!';
        }
    }
    $z++;
}

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