如何在PHP中的不同变量中存储数组元素 [英] How to store array elemnts in diffrent variables in php
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问题描述
我有一个选择的语言下拉列表，我很想把数组的每个元素都放在diffrent变量中.为了让您理解我的问题，我将在此处输入代码:
I have a select drop down list of languages and I'm intrested of putting each element of the array in diffrent variable. For you understanding my question I will put here a code:
<html dir="ltl">
<?php
header('Content-Type: text/html; charset=utf-8');
$db=mysqli_connect("localhost","root","","travelersdb");
mysqli_query($db,"SET NAMES 'utf8'");
?>
<head>
<link href="Styles/StyleEx.css" rel="stylesheet" type="text/css"/>
</head>
<script type="text/javascript">
var expanded = false;
function showCheckboxes() {
var checkboxes = document.getElementById("checkboxes");
if (!expanded) {
checkboxes.style.display = "block";
expanded = true;
} else {
checkboxes.style.display = "none";
expanded = false;
}
}
</script>
<body>
<tr>
<td>Languages</td>
<td dir="rtl">
<form method="post" action="exxx.php">
<div class="multiselect" dir="rtl">
<div class="selectBox" onclick="showCheckboxes()" dir="rtl">
<select>
<option>Choose language:</option>
</select>
<div class="overSelect" dir="rtl"></div>
</div>
<div id="checkboxes">
<label for="one">
<input type="checkbox" id="one" name="languages[]" value="English">English</label>
<label for="two">
<input type="checkbox" id="two" name="languages[]" value="German" >German</label>
<label for="three">
<input type="checkbox" id="three" name="languages[]" value="French">French</label>
<label for="four">
<input type="checkbox" id="four" name="languages[]" value="Spanish">Spanish</label>
<label for="five">
<input type="checkbox" id="five" name="languages[]" value="Italien">Italien</label>
</div>
</div>
<input type="submit" name="submit">
</form>
</td>
</tr>
<?php
if (isset($_POST['submit'])) {
$languages = $_POST['languages'];
$language1 = $languages[0];
$language2 = $languages[1];
$language3 = $languages[2];
$language4 = $languages[3];
$language5 = $languages[4];
echo $language1;
echo $language2;
echo $language3;
echo $language4;
echo $language5;
}
?>
</body>
</html>
如果我选中所有复选框，则没有问题，但是如果我选中的复选框少于5个，我将收到此消息:
If I'm checking all the checkboxs there isn't a problem but if I'm checking less then 5 I will get this message:
Notice: Undefined offset:
这是因为数组大小.如果检查的语言少于5种，如何避免这种情况并回显变量?
This is beacuse of the array size. How can I avoid this and echo the variables if there were less than 5 languages checked?
推荐答案
您可以使用$$定义变量.查看 实时演示
You can use $$ to define a variable. check the live demo
请注意，您可以访问foreach范围之外的所有变量.
foreach($languages as $k => $v)
{
$name = 'language' . ($k + 1);
$$name = $v;
}
print_r($language1);
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