获取结构数组中的索引 [英] Get the index in a structure array

问题描述

我有这个在tcl中的结构数组

I have this structure array which is in tcl

A = {1 2 3} {4 5 6} {7 8 9} {1 4 10}

A={1 2 3} { 4 5 6 } {7 8 9} {1 4 10}

我想获取结构索引，该索引包含数字4(应为2，在A中为4)；我该怎么办?

I would like to get the structure indices which contain the number 4 which should be 2 , and 4 in A; how could I do it?

同样，在我能够获得该索引之后，我想删除那些结构，以便

Also after i was able to get that indices , i'd like to remove those structures so that

A = {1 2 3} {7 8 9}

A={1 2 3}{7 8 9}

我该怎么做?

谢谢！

推荐答案

[lmap] 可以提供帮助. [continue] 允许您跳过以下项目:

[lmap] can help with that. [continue] allows you to skip the item:

set A {{1 2 3} {4 5 6} {7 8 9} {1 4 10}}
set B [lmap x $A {
                    if {[lsearch -exact $x 4] >= 0} {
                        continue
                    } else {
                        set x
                    }
                }]
    puts $B

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