C语言中的反向词 [英] Reverse words in C Language
本文介绍了C语言中的反向词的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正试图反转句子中单词的字母.我也试图将这些单词存储在一个新的char数组中.目前,我遇到了运行时错误,对于我所有的调整,我都无法解决.我的方法是创建一个与句子长度相同的新char数组.然后循环遍历该句子,直到我到达''字符为止.然后向后循环,并将这些字符添加到单词中.然后将单词添加到新的句子中.任何帮助将不胜感激.
I'm trying to reverse the letters for words in a sentence. I am also trying to store these words in a new char array. At the moment I getting a runtime error, which for all my tweaking I can not solve. My approach is to create a new char array the same length as the sentence. Then loop through the sentence until I reach a ' ' character. Then loop backwards and add these characters to a word. Then add the word to the new Sentence. Any help would be much appreciated.
int main(void) {
char sentence [] = "this is a sentence";
char *newSentence = malloc(strlen(sentence)+1);
int i,j,start;
start = 0;
for(i = 0; i <= strlen(sentence); i++)
{
if(sentence[i] == ' ')
{
char *word = malloc((i - start)+1);
for(j = sentence[i]; j >= start; j--)
{
word[j] = sentence[j];
}
strcat(newSentence,word);
start =sentence[i +1];
}
}
printf("%s",newSentence);
return 0;
}
推荐答案
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void) {
char sentence [] = "this is a sentence";
char *newSentence;
int i,j,start, len;
start = 0;
len = strlen(sentence);
newSentence = malloc(len+1);
*newSentence = '\0';
for(i = 0; i <= len; i++)
{
if(sentence[i] == ' ' || sentence[i] == '\0')
{
char *word = malloc((i - start)+1);
int c = 0;
for(j = i - 1; j >= start; j--)
{
word[c++] = sentence[j];
}
word[c]='\0';
strcat(newSentence,word);
if(sentence[i] == ' ')
strcat(newSentence," ");
start = i + 1;
free(word);
}
}
printf("%s",newSentence);
return 0;
}
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