返回任务时链接任务的正确方法是什么? [英] What is the proper way to chain Tasks when returning a Task?
问题描述
我在C#中使用Tasks是如此,但是当我尝试从一个方法返回Task时,我感到困惑,并且该方法将在自身内部执行多个任务.那么,是否让我的方法启动一个新的Task,然后依次执行其中的所有任务?.ContinueWith()
I am so so with using Tasks in C# but I get confused when I try to return a Task from a method and that method will do multiple tasks within itself. So do I have my method spin up a new Task and then do everything sequentially inside of there? It's hard to wrap my head around doing it all with .ContinueWith()
示例:
public Task<string> GetSomeData(CancellationToken token)
{
return Task.Factory.StartNew(() =>
{
token.ThrowIfCancellationRequested();
var initialData = GetSomeInteger(token).Result;
return GetSomeString(initialData, token).Result;
});
}
public Task<int> GetSomeInteger(CancellationToken token)
{
return Task<int>.Factory.StartNew(() =>
{
return 4;
}, token);
}
public Task<string> GetSomeString(int value, CancellationToken token)
{
return Task<string>.Factory.StartNew(() =>
{
return value.ToString();
}, token);
}
我不确定如何再编写此方法以使其正确使用Tasks.我想我只是觉得里面应该有一个.ContinueWith之类的东西.
I am unsure how else to write this method to make it use Tasks correctly. I guess I just feel like there should be a .ContinueWith in there or something.
可能的解决办法?
public Task<string> GetSomeData(CancellationToken token)
{
return GetSomeInteger(token).ContinueWith((prevTask) =>
{
return GetSomeString(prevTask.Result, token);
}, token).Unwrap();
}
推荐答案
通常,如果您已经在使用基于任务的方法,通常最好避免重复处理新任务.链接任务而不是显式阻塞将减少系统的开销,因为它不会使ThreadPool线程一直处于等待状态.
In general, it's often best to try to avoid spinning up new tasks if you are already working with task-based methods. Chaining tasks instead of blocking explicitly will reduce the overhead of the system, as it won't keep a ThreadPool thread tied up waiting.
话虽这么说,但在执行操作时仅阻塞通常会更简单.
That being said, it's often simpler to just block as you're doing.
请注意,C#5使这一过程变得更加简单,它提供了可以同时兼顾两者的API:
Note that C# 5 makes this far simpler, providing an API that gives you the best of both:
public async Task<string> GetSomeData(CancellationToken token)
{
token.ThrowIfCancellationRequested();
var initialData = await SomeOtherMethodWhichReturnsTask(token);
string result = await initialData.MethodWhichAlsoReturnsTask(token);
return result;
};
更新后
鉴于新代码,没有一种简单的方法可以直接将其与 ContinueWith
链接起来.有两种选择.您可以使用展开来转换 Task< Task< string>>
您将创建的,即:
Given the new code, there isn't an easy way to chain this directly with ContinueWith
. There are a couple of options. You can use Unwrap to convert the Task<Task<string>>
you'd create, ie:
public Task<string> GetSomeData(CancellationToken token)
{
Task<Task<string>> task = GetSomeInteger(token)
.ContinueWith(t =>
{
return GetSomeString(t.Result, token);
}, token);
return task.Unwrap();
}
或者,您可以使用 TaskCompletionSource< T>
:
Alternatively, you can handle the unwrapping yourself elegantly with TaskCompletionSource<T>
:
public Task<string> GetSomeData(CancellationToken token)
{
var tcs = new TaskCompletionSource<string>();
Task<int> task1 = GetSomeInteger(token);
Task<Task<string>> task2 = task1.ContinueWith(t => GetSomeString(t.Result, token));
task2.ContinueWith(t => tcs.SetResult(t.Result.Result));
return tcs.Task;
}
这使整个过程可以正常工作,而无需创建新的Task(将线程池线程捆绑在一起),也不会阻塞.
This allows the entire process to work without creating a new Task (which ties up a threadpool thread), and without ever blocking.
请注意,您可能希望添加取消后的延续,并使用 tcs.也可以在请求取消时使用SetCancelled .
Note that you would probably want to add continuations on cancellation, and use tcs.SetCancelled when a cancellation was requested, as well.
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