给定排序字符串的游程长度编码 [英] Run-length encoding of a given sorted string

问题描述

为给定字符串的运行长度编码编写代码
样本输入:aaaaaaaaaabcabcccccc
输出:a10bc6

Write code for run -length encoding of a given string
Sample Input: aaaaaaaaaabcccccc
Output: a10bc6

我的代码:

static void Main(string[] args)
{
    string str = "aaaaaaaaaabcccccc";
    var qry = (from c in str
               group c by c into grp
               select new
               {
                   output = grp.Key.ToString() + grp.Count().ToString()
               });
    StringBuilder sb = new StringBuilder();
    foreach (var item in qry)
    {
        sb.Append(item.output);
    }
    Console.WriteLine(sb.ToString());
    Console.ReadLine();
}

但是它返回:

a10b1c6

a10b1c6

我要删除非重复字符的计数，这是字母'b'的"1".

I want to remove the count for non-repeating char, here is "1" for letter 'b'.

假定它是一个排序的字符串.

Assume that it is a sorted string.

推荐答案

以下是简化版本:

public static void Main()
{
   string str = "aaaaaaaaaabcccccc";
    var qry = (from c in str
               group c by c into grp
               let c = grp.Count()
               select grp.Key.ToString() + (c > 1 ? c.ToString() : ""));

    Console.WriteLine(string.Join("",qry));
    Console.ReadLine();
}

您需要注意三元表达式周围的括号位置，然后我使用了 string.Join 来避免使用 for每个循环和字符串生成器的麻烦

You need to be careful with the bracket placement around the ternary expression, and then I used string.Join to avoid the mess with a for each loop and string builder.

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