在控制台应用程序中启动WPF应用程序 [英] Start WPF Application in Console Application

问题描述

是否可以在控制台模式下启动WPF应用程序?

Is it possible to start WPF Application in Console mode?

public partial class App : Application
{
    public App()
    {
        InitializeComponent();
    }
}

<Application x:Class="WPF.App"
         xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
         xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
</Application>

[STAThread]
static void Main(string[] args)
{
  if (args.Length > 0)
  {
     switch (args[0].ToLower())
     {
       case "/g": RunApplication(); break;
     }
  }
}

private static void RunApplication()
{
    var application = new System.Windows.Application();

    application.Run(new App());
}

它将显示参数类型"WPF.app"不可分配给参数类型"System.Windows.Window".

It will show Argument type 'WPF.app' is not assignable to parameter type 'System.Windows.Window'.

解决任何可行的解决方案??

Any solution to work around it?? Any different between

1.public局部类App:应用程序

1.public partial class App : Application

2.public局部类App:Window

2.public partial class App : Window

推荐答案

您可以声明一个Window，然后以这种方式启动您的应用程序:

You could declare a Window and then start your app this way:

var application = new System.Windows.Application();
application.Run(new Window());

您似乎有些困惑，所以让我解释一下:

You seem a bit confused, so let me explain:

假设您有一个程序:

using System;

namespace ConsoleApplication
{
    class Program
    {
        [STAThread]
        static void Main(string[] args)
        {
            RunApplication();
        }

        private static void RunApplication()
        {
            var application = new System.Windows.Application();
            application.Run();
        }
    }
}

这将在没有窗口的情况下运行WPF应用程序.

This will run a WPF application with no Window.

另一方面，如果将Window传递到application.Run()，则将获得WPF窗口.App不应该从Window派生，因为它应该从Application派生.

If, on the other hand, you pass a Window into application.Run(), you will get a WPF window. App should not derive from Window, since it should derive from Application.

Application.Run方法不带参数或不带窗口.它不需要应用程序.因此，如果要启动以前创建的应用程序，就应该执行以下操作:

Application.Run method either takes no arguments or a Window. It does not take Application. Therefore, if you want to start a previously created Application, as you have over there, you should do something like this:

private static void RunApplication()
{
    var application = new App();
    application.Run();  // add Window if you want a window.
}

最后，如果您只想使用 application.Run()而不需要传递特定的Window，只需使用StartupUri在Application XAML中声明一个启动Window:

Lastly, if you want to just use application.Run() and not have to pass a specific Window, just declare a starting Window in your Application XAML using StartupUri:

<Application x:Class="WPF.App"
         xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
         xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
         StartupUri="SomeWindow.xaml">
</Application>

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