Rhino Mocks-模拟一个方法,该方法的多次调用会改变返回值(即使传递了相同的参数) [英] Rhino Mocks - mocking a method whose return value changes (even when passed the same parameter) with multiple calls
问题描述
我正在寻找一种方法,该方法可以模拟一个方法,该方法在第二次调用第一次时将返回一个不同的值.例如,如下所示:
I'm looking to find out how I can mock a method that returns a different value the second time it is called to the first time. For example, something like this:
public interface IApplicationLifetime
{
int SecondsSinceStarted {get;}
}
[Test]
public void Expected_mock_behaviour()
{
IApplicationLifetime mock = MockRepository.GenerateMock<IApplicationLifetime>();
mock.Expect(m=>m.SecondsSinceStarted).Return(1).Repeat.Once();
mock.Expect(m=>m.SecondsSinceStarted).Return(2).Repeat.Once();
Assert.AreEqual(1, mock.SecondsSinceStarted);
Assert.AreEqual(2, mock.SecondsSinceStarted);
}
有什么可以做到这一点的吗?除了为实现状态机的getter实现一个sub之外?
Is there anything that makes this possible? Besides implementing a sub for the getter that implements a state machine?
推荐答案
您可以使用 .WhenCalled
方法拦截返回值.请注意,您仍然需要通过 .Return
方法提供一个值,但是,如果从方法调用中更改了 ReturnValue
,Rhino只会忽略该值:
You can intercept return values with the .WhenCalled
method. Note that you still need to provide a value via the .Return
method, however Rhino will simply ignore it if ReturnValue
is altered from the method invocation:
int invocationsCounter = 1;
const int IgnoredReturnValue = 10;
mock.Expect(m => m.SecondsSinceLifetime)
.WhenCalled(mi => mi.ReturnValue = invocationsCounter++)
.Return(IgnoredReturnValue);
Assert.That(mock.SecondsSinceLifetime, Is.EqualTo(1));
Assert.That(mock.SecondsSinceLifetime, Is.EqualTo(2));
深入研究一下,看来 .Repeat.Once()
确实在这种情况下确实可以工作,并且可以用来实现相同的结果:>
Digging around a bit more, it seems that .Repeat.Once()
does indeed work in this case and can be used to achieve the same result:
mock.Expect(m => m.SecondsSinceStarted).Return(1).Repeat.Once();
mock.Expect(m => m.SecondsSinceStarted).Return(2).Repeat.Once();
mock.Expect(m => m.SecondsSinceStarted).Return(3).Repeat.Once();
在连续调用时将返回1、2、3.
Will return 1, 2, 3 on consecutive calls.
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