如何实例化List< T>但是直到运行时T才是未知的? [英] How to instantiate List<T> but T is unknown until runtime?

问题描述

假设我有一个直到运行时才知道的类.在运行时，我得到类型为Foo.GetType()的Type类型的引用x.只有使用x和List<>，我才能创建Foo类型的列表吗?

Assume I have a class that is unknown until runtime. At runtime I get a reference, x, of type Type referencing to Foo.GetType(). Only by using x and List<>, can I create a list of type Foo?

该怎么做?

推荐答案

Type x = typeof(Foo);
Type listType = typeof(List<>).MakeGenericType(x);
object list = Activator.CreateInstance(listType);

当然，您不应期望此处有任何类型的安全性，因为在编译时结果列表的类型为 object .使用 List< object> 会更实用，但类型安全仍然有限，因为 Foo 的类型仅在运行时才知道.

Of course you shouldn't expect any type safety here as the resulting list is of type object at compile time. Using List<object> would be more practical but still limited type safety because the type of Foo is known only at runtime.

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