如何用罗琳得到一种方法的身体? [英] How to get il of one method body with roslyn?

问题描述

我想在我的C#源代码文件中找到一种方法，我已经用roslyn打开解决方案并找到如下所示的方法符号

I want to get il of one method in my c# source code file.I have opened solution with roslyn and find the method symbol like below

Roslyn.Compilers.Common.ISymbol s=GetMethodSymbolAtPosition (30);

我有一个ISymbol，现在怎么会患病?

I have an ISymbol how get il now?

推荐答案

不幸的是，IL生成完全隐藏在Roslyn的 Emit 调用中.但我给您一个简单的入门方法.

Unfortunately, the IL generation is entirely hidden inside the Emit call in Roslyn. But I'll give a simple to get you started.

假设您从现有的编译开始:

Let's suppose you start of with an existing compilation:

var initial = CSharpCompilation.Create("Existing")
    .AddReferences(MetadataReference.CreateFromFile(typeof(object).Assembly.Location))
    .AddSyntaxTrees(SyntaxFactory.ParseSyntaxTree(@"    
        namespace Test
        {
            public class Program
            {
                public static void HelloWorld()
                {
                    System.Console.WriteLine(""Hello World"");
                }
            }
        }"));    
var method = initial.GetSymbolsWithName(x => x == "HelloWorld").Single();

其中 method 是您的 ISymbol .然后您可以执行以下操作:

where method is your ISymbol. Then you can do following:

// 1. get source
var methodRef = method.DeclaringSyntaxReferences.Single();
var methodSource =  methodRef.SyntaxTree.GetText().GetSubText(methodRef.Span).ToString();

// 2. compile in-memory as script
var compilation = CSharpCompilation.CreateScriptCompilation("Temp")
    .AddReferences(initial.References)
    .AddSyntaxTrees(SyntaxFactory.ParseSyntaxTree(methodSource, CSharpParseOptions.Default.WithKind(SourceCodeKind.Script)));

using (var dll = new MemoryStream())
using (var pdb = new MemoryStream())
{
    compilation.Emit(dll, pdb);

    // 3. load compiled assembly
    var assembly = Assembly.Load(dll.ToArray(), pdb.ToArray());
    var methodBase = assembly.GetType("Script").GetMethod(method.Name, new Type[0]);

    // 4. get il or even execute
    var il = methodBase.GetMethodBody();
    methodBase.Invoke(null, null);
}

在更复杂的情况下，您可能需要发出整个/初始编译，并通过反射获取生成的方法.

In a more complex case, you'd probably need to emit the entire/initial compilation, and get the generated method via reflection.

请参阅此发布以找出您可以对 GetMethodBody()的结果执行的操作.

Refer to this post to find out what you can do with the results of GetMethodBody().

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