通用类型列表 [英] List of generic Type
本文介绍了通用类型列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个通用类,我想创建一个列表.然后在运行时我得到了物品的类型
I have a generic class and I want to create a list of it. and then at run time I get the type of the item
public class Job<T>
{
public int ID { get; set; }
public Task<T> Task { get; set; }
public TimeSpan Interval { get; set; }
public bool Repeat { get; set; }
public DateTimeOffset NextExecutionTime { get; set; }
public Job<T> RunOnceAt(DateTimeOffset executionTime)
{
NextExecutionTime = executionTime;
Repeat = false;
return this;
}
}
我想实现的目标
List<Job<T>> x = new List<Job<T>>();
public void Example()
{
//Adding a job
x.Add(new Job<string>());
//The i want to retreive a job from the list and get it's type at run time
}
推荐答案
如果您的所有作业都属于同一类型(例如 Job< string>
),则可以简单地创建该类型的列表:
If all of your jobs are of same type (e.g. Job<string>
) you can simply create a list of that type:
List<Job<string>> x = new List<Job<string>>();
x.Add(new Job<string>());
但是,如果要在同一列表中混合使用不同类型的作业(例如 Job< string>
和 Job< int>
),则必须创建一个非通用基类或接口:
However, if you want to mix jobs of different types (e.g. Job<string>
and Job<int>
) in the same list, you'll have to create a non-generic base class or interface:
public abstract class Job
{
// add whatever common, non-generic members you need here
}
public class Job<T> : Job
{
// add generic members here
}
然后您可以执行以下操作:
And then you can do:
List<Job> x = new List<Job>();
x.Add(new Job<string>());
如果您想在运行时获取 Job
的类型,可以执行以下操作:
If you wanted to get the type of a Job
at run-time you can do this:
Type jobType = x[0].GetType(); // Job<string>
Type paramType = jobType .GetGenericArguments()[0]; // string
这篇关于通用类型列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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