下一个最近的数字可被X整除 [英] Next Nearest Number Divisible By X

问题描述

我想做的基本上是取用户输入的任何数字，然后将其四舍五入为X可以除的下一个最接近的整数，不包括1.

What I want to do essentially, is take any number a user has input, and round it to the next closest whole number divisible by X, excluding 1.

IE(X = 300):

IE (X = 300):

输入= 1输出= 300

Input = 1 Output = 300

输入= 500输出= 600

Input = 500 Output = 600

输入= 841输出= 900

Input = 841 Output = 900

输入= 305输出= 300

Input = 305 Output = 300

推荐答案

(整数)除以X，加一，然后乘以X.

Just (integer) divide by X, add one, then multiply by X.

int output = ((input / x) + 1) * x;

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