使用自己的应用程序打开自定义文件 [英] Open custom file with own application

问题描述

可能重复:
如何关联文件扩展名到C#中的当前可执行文件

所以，我正在申请学校(最终项目).

So, I'm making an application for school (final project).

在此应用程序中，我有一个 Project 类.可以将其另存为自定义文件，例如测试. gpr .(.gpr是扩展名).

In this application, I have a Project-class. This can be saved as a custom file, e.g. Test.gpr. (.gpr is the extension).

如何让Windows/我的应用程序将.gpr文件与此应用程序相关联，因此，如果我双击.gpr文件，则我的应用程序将启动并打开该文件(因此启动OpenProject方法-这将加载项目).

How can I let windows/my application associate the .gpr file with this application, so that if I doubleclick the .gpr file, my application fires and opens the file (so launches the OpenProject method - This loads the project).

我不询问如何让Windows将文件类型与应用程序相关联，我询问如何在Visual Studio 2012的代码中捕获该问题.

I am NOT asking how to let windows associate a file type with an application, I am asking how to catch this in my code in Visual Studio 2012.

更新:由于我的问题似乎不太清楚:

UPDATE: Since my question seems to be not so clear:

atm，我什么也没做，所以我可以遵循最佳解决方案.我想要的就是双击.gpr，确保Windows知道可以使用我的应用程序打开它，并在我的应用程序中捕获文件路径.

atm, I've done nothing, so I can follow whatever is the best solution. All I want is to doubleclick the .gpr, make sure windows knows to open it with my app, and catch the filepath in my application.

任何帮助将不胜感激！

推荐答案

使用应用程序打开文件时，该文件的路径将作为第一个命令行参数传递.

When you open a file with an application, the path to that file is passed as the first command line argument.

在C#中，这是 Main 方法的 args [0] .

In C#, this is args[0] of your Main method.

static void Main(string[] args)
{
    if(args.Length == 1) //make sure an argument is passed
    {
        FileInfo file = new FileInfo(args[0]);
        if(file.Exists) //make sure it's actually a file
        {
           //Do whatever
        }
    }

    //...
}

---

WPF

如果您的项目是WPF应用程序，请在 App.xaml 中添加 Startup 事件处理程序:

<Application x:Class="WpfApplication1.App"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             StartupUri="MainWindow.xaml"
             Startup="Application_Startup"> <!--this line added-->
    <Application.Resources>

    </Application.Resources>
</Application>

您的命令行参数现在将位于 Application_Startup 事件处理程序的 e.Args 中:

Your command line arguments will now be in e.Args of the Application_Startup event handler:

private void Application_Startup(object sender, StartupEventArgs e)
{
    if(e.Args.Length == 1) //make sure an argument is passed
    {
        FileInfo file = new FileInfo(e.Args[0]);
        if(file.Exists) //make sure it's actually a file
        {
           //Do whatever
        }
    }
}

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