如何降低Switch案例陈述的循环复杂性 [英] How to reduce Cyclomatic complexity of Switch case statements

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本文介绍了如何降低Switch案例陈述的循环复杂性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

有一个带有开关盒的功能,我们需要减少它的CC

There is an function which has switch case and we need to reduce its CC

       string data = string.empty;
       switch (value)
        {
            case "Less than 2 billion":
                data = "0 - 2B";
                break;
            case "2 billion to 10 billion":
                data = "2B - 10B";
                break;
            case "10 billion to 20 billion":
                data = "10B - 20B";
                break;
            case "20 billion to 50 billion":
                data = "20B - 50B";
                break;
            case "Greater than 50 billion":
                data = "> 50B";
                break;
            case "N/A":
                data = "N/A";
                break;
            case "[items] > 0":
                data = string.Empty;
                break;
        }
        return data;

推荐答案

在这种情况下,您可以使用字典查找,这样可以节省一些代码并且更加清晰.

You could use a dictionary lookup in this case, it would be a little less code and clearer.

这篇关于如何降低Switch案例陈述的循环复杂性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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