如何从Roslyn中的using指令获取完全限定的名称空间? [英] How can I get the fully qualified namespace from a using directive in Roslyn?

问题描述

当您将鼠标悬停在VS2015中的简化的 using 指令"上时，它将显示标准名称.如何通过Roslyn插件获取此信息?它会使用 DiagnosticAnalyzer 吗? CodeFixProvider ?

When you hover over a "simplified" using directive in VS2015, it shows you the fully-qualified name. How would I get this information via a Roslyn plugin? Would it be using a DiagnosticAnalyzer? A CodeFixProvider?

通读source.roslyn.codeplex.com，那里有大量信息，包括如何

Reading through source.roslyn.codeplex.com, there's tons of information there, including how to add a using statement, and also how to simplify type names (including using statements), but I'm unable to figure out how to go in reverse to get the fully-qualified name.

推荐答案

使用语义模型，您可以(显然)检索有关组成代码的语义的信息-这使您可以获得有关类型和其他构造的特定信息..

With the semantic model you can retrieve information about the semantics that make up your code (evidently) -- this allows you to get specific information about types and other constructs.

例如:

void Main()
{
    var tree = CSharpSyntaxTree.ParseText(@"
using X = System.Text;
using Y = System;
using System.IO;

namespace ConsoleApplication1
{
}"
);

    var mscorlib = PortableExecutableReference.CreateFromFile(typeof(object).Assembly.Location);
    var compilation = CSharpCompilation.Create("MyCompilation", syntaxTrees: new[] { tree }, references: new[] { mscorlib });
    var semanticModel = compilation.GetSemanticModel(tree);
    var root = tree.GetRoot();

    // Get usings
    foreach (var usingDirective in root.DescendantNodes().OfType<UsingDirectiveSyntax>())
    {
        var symbol = semanticModel.GetSymbolInfo(usingDirective.Name).Symbol;
        var name = symbol.ToDisplayString(SymbolDisplayFormat.FullyQualifiedFormat);
        name.Dump();
    }
}

输出:

global :: System.Text
全局::系统
全局:: System.IO

global::System.Text
global::System
global::System.IO

如果您改用 SymbolDisplayFormat.CSharpErrorMessageFormat ，则会收到

System.Text
系统
System.IO

System.Text
System
System.IO

您可以选择自己感兴趣的内容，但是可以看到，无论有没有别名，它都可以正常工作.

Your choice what you're interested in but as you can see it works just fine with aliases and without.

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