PHP缓存包含文件 [英] PHP caching include file

问题描述

我在test.php中有以下测试代码:

I have the following test code in test.php:

<?php
$step = $_GET['step'];
switch($step) {
  case 1:
    include 'foo.php';   # line 5
    file_put_contents('foo.php', '<?php print "bar\\n"; ?>');
    header('Location: test.php?step=2');
  break;
  case 2:
    print "step 2:\n";
    include 'foo.php';
  break;
}
?>

foo.php最初具有以下内容:

foo.php initially has the following content:

<?php print "foo\n"; ?>

当我在浏览器中调用test.php?step = 1时，我会期望得到以下输出:

When I call test.php?step=1 in my browser I would expect the following output:

step 2:
bar

但我得到以下输出:

step 2:
foo

当我注释掉第5行中的include时，我得到了期望的结果.结论是，PHP缓存了foo.php的内容.当我用step = 2重新加载页面时，我也得到了预期的结果.

When I comment out the include in line 5, I get the desired result. The conclusion is, that PHP caches the content of foo.php. When I reload the page with step=2 I also get the desired result.

现在...这是为什么，以及如何避免这种情况?

Now... why is this and how to avoid this?

推荐答案

假设您使用OPcache， opcache.enable = 0 可以工作.

Assuming you use OPcache, opcache.enable = 0 works.

一种更有效的方法是使用

A more efficient method is to use

opcache_invalidate ( string $script [, boolean $force = FALSE ] )

这将从内存中删除脚本的缓存版本，并强制PHP重新编译.

This will remove the cached version of the script from memory and force PHP to recompile.

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