表示日历事件的摆动JComponent的布局管理器 [英] Layout manger for swing JComponents representing calendar events

问题描述

我正在开发一个Java应用程序，需要在其中将代表日历事件的JComponent布局在一个容器中:

I am working on a java app in which I need to layout JComponents representing calendar events, in a container:

我使用自定义布局管理器，我怀疑是否是正确的解决方案.我根据事件的开始和结束时间计算顶部x位置和高度.我还计算每个事件的重叠事件数，从而计算出最大重叠数(代表最大列数).

I use custom layout manager, and I doubt if is the right solution. I calculate the top x position and the height, based on the event start and end time. I also calculate the number of overlapping events for each event, and as a result the max number of overlaps (which represents the max number of columns).

在计算每个组件的y位置和宽度时，由于存在许多重叠的可能性，因此变得很复杂.

When it comes to calculating y position and width of each component, it gets complicated because of many overlapping possibilities.

我的问题:是否有可用的布局管理器可以帮助我优化此类布局?还是应该继续使用和改进自定义布局管理器?

My question: is there an available layout manager which can help me optimize such layout ? or should I continue the using and improving the custom layout manager ?

推荐答案

在研究了各种布局管理器之后，对我来说很明显，需要完成的工作中最重要的部分是计算约束.

After exploring various layout managers, it became clear to me the most significant part of the work that needs to be done, is calculation the constrains.

我使用了以下方法:

对于代表一天的每个容器:

For each container representing a day :

• 根据时标计算每个JComponent的Y位置(垂直)和高度(代表单个日历事件).
• 要计算每个JComponent的X位置和宽度，我必须分析重叠的组件，并找出每个子列"(或子列 s )应该占据的位置.
• 遍历所有容器的JComponent(按高度排序，代表持续时间)，针对所有其他JComponent进行时间重叠的JComponent检查.这样做，我能够计算出每个JComponent所需的子列数和相应的子列(X位置).
• 基于每个JComponent的X位置，我能够通过搜索下一个重叠的JComponent(如果有)来计算其宽度.下一个重叠的JComponent的X位置限制了宽度.

在具有所有需要的约束之后，我可以使用简单的布局管理器(如Formlayout)，但是我看不到这样做的价值.为每个JComponent设置界限很简单.

After having all the needed constrains, I could use a simply layout manager (like Formlayout), but I did not see the value of doing so. Setting bounds for each JComponent was straight forward.

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