循环创建单元格数组 [英] Loop to create cell array
问题描述
我有一个名为 data
的结构.该结构包含250个元素和一个称为 codes
的字段(其尺寸各不相同).
I have a structure named data
. The structure has 250 elements and one field called codes
(whose dimension varies).
例如: data(1).codes
是一个 300 x 1
字符串单元格,而 data(2).codes
是一个 100 x 1
字符串单元格.
As an example: data(1).codes
is a 300 x 1
cell of strings and data(2).codes
is a 100 x 1
cell of strings.
我想做的是创建一个具有三列的大单元格: id计数代码
其中 id
索引元素编号(1到250), count
索引字符串的行,而 codes
只是代码.
What I am trying to do is to create a big cell with three columns: id count codes
where id
indexes the element number (1 to 250), count
indexes the row of the string and codes
are just the codes.
一个清楚的例子:
for k = 1:size(data,2)
id = repmat(k,size(data(k).codes,1),1);
count = linspace(1, size(data(k).codes,1), size(data(k).codes,1))';
codes= data(k).codes;
end
上面的循环创建我想要的列.现在,我只需要将它们一个附加在另一个下面,然后保存为excel.如果只有这些,我知道如何连接/附加矩阵.但是对于细胞,我不确定该怎么做.
The loop above creates the columns I want. Now I just need to append them one below the other and then save to excel. If these where only numbers I knew how to concatenate/append matrices. But with cells I am unsure how to do it.
这是我尝试过的:
output = {};
for k = 1:size(data,2)
id = repmat(k,size(data(k).codes,1),1);
count = linspace(1, size(data(k).codes,1), size(data(k).codes,1))';
codes= data(k).codes;
output{1,1} = {output{1,1}; id};
output{1,2} = {output{1,2}; count};
output{1,3} = {output{1,3};
end
推荐答案
将您的输出构建到新的单元格数组中,以便进行预分配,然后将所有结果串联起来.
Build up your output into a new cell array, allowing for pre-allocation, then concatenate all of your results.
% Initialise
output = cell(size(data,2), 1);
% Create output for each element of data
for k = 1:size(data,2)
id = repmat(k,size(data(k).codes,1),1);
count = linspace(1, size(data(k).codes,1), size(data(k).codes,1))';
codes = data(k).codes;
% add to output
output{k} = [id, count, codes];
end
% Vertically concatenate all cell elements
output = vertcat(output{:});
注意:这假定 codes
是数字,并且输出将是数字矩阵.如果不是,您将需要对数字数据( id
和 count
)进行一些单元格转换,如下所示:
Note: this assumes codes
is numerical, and the output will be a numerical matrix. If it isn't, you will need to do some cell conversions for your numerical data (id
and count
) like so:
id = repmat({k}, size(data(k).codes,1), 1);
count = num2cell(linspace( ... )');
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