Google图表:如何将参数传递给回调(JavaScript)? [英] Google Charts: How to pass a parameter into a callback (JavaScript)?

问题描述

我有以下代码:

google.charts.setOnLoadCallback( drawChart );
function drawChart() { ... }

我需要将一个称为chartID的参数传递给drawChart()函数.我该怎么做?似乎Google图表不想获取任何参数:)有任何想法吗?

I need to pass a parameter called chartID into a drawChart() function. How can I do it? Seems google chart doesn't want to get any params :) Any ideas?

推荐答案

一种方法是添加另一个功能...

one way is to add another function...

google.charts.setOnLoadCallback(function () {
  drawChart(chartID);
});

function drawChart(chartID) { ... }

这篇关于Google图表:如何将参数传递给回调(JavaScript)?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！