如何确定折线图原点的像素位置? [英] How to determine pixel position of line chart origin?

问题描述

JavaFX LineChart由绘图区域和轴组成.由于轴渲染使用了一些显示空间，因此折线图中原点的位置不是(0，0).如何获得相对于折线图本身位置的位置?

A JavaFX LineChart consists of the plot area and axes. Since the axes rendering uses some display space, the position of the origin in a line chart is not (0, 0). How do I get this position relative to the position of the line chart itself?

我想相对于折线图的位置来计算绘图区域中点的位置.x轴和y轴的 getDisplayPosition 方法提供了相对于原点的相对位置，但是我没有找到一种明显的方法来获取原点位置.

I'd like to calculate the position of a point in the plot area relative to the position of the line chart. The getDisplayPosition method of the x- and y-axis provide this relative to the origin but I don't see an obvious way to get the origin position.

推荐答案

更好的观察方法是通过 chart.lookup 命令获取绘图区域，如下所示:

Much better way as observing is to get the plot-area by the chart.lookup command like this:

//gets the display region of the chart
Node chartPlotArea = chart.lookup(".chart-plot-background");
double chartZeroX = chartPlotArea.getLayoutX();
double chartZeroY = chartPlotArea.getLayoutY();

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