在命令行中从不同的程序包访问类 [英] Accessing class from different package in command line

问题描述

我在C:\ Users \ Documents文件夹中创建了两个文件夹.我将文件夹命名为A和B.在文件夹A内，我在Java类下面编写了代码.

I have created two folders in C:\Users\Documents folder. I have named the folders as A and B. Inside folder A, I have written below java class.

package A;

public class Food {
int a =6;
public int c = 10;
}

在文件夹B中，我写了下面的课，

Inside folder B, I have below class written,

package B;
import A.*;

public class Car {
 public static void main(String[] args) {
     Food food = new Food();
     System.out.println(food.c);         

 }
}

我能够从文件夹A内编译Food类.但是，当我尝试从文件夹B内编译Car类时，出现以下编译错误.该如何解决?

I am able to compile class Food from inside folder A. But when I am trying to compile class Car from inside folder B, I am getting below compilation error. How to resolve this?

Car.java:2: error: package A does not exist
import A.*;
^
Car.java:6: error: cannot find symbol
     Food food = new Food();
     ^
symbol:   class Food
location: class Car
Car.java:6: error: cannot find symbol
     Food food = new Food();
                 ^
symbol:   class Food
location: class Car
3 errors

推荐答案

您应该位于 Documents 文件夹中，才能同时访问A和amp;B，同时编译 Car 类.

You should be in the Documents folder to get access both the packages A & B while compiling Car class.

您的编译语句必须类似于

And your compile statement must be something like

javac -cp . B/Car.java

注意:考虑到.class文件在下面，我将类路径作为当前目录(.).

要运行 Car 类，请使用以下命令.

To run the class Car use the below command.

java -cp . B.Car

使用main()运行Class时，您需要给出类名的完整限定路径，即 packagename.className

While running Class with main(), you need to give full qualified path of class name i.e. packagename.className

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