退出主要.py文件时无法打开另一个.py文件 [英] Unable to open another .py file on exiting the primary .py file

问题描述

我已经创建了2个 .py 文件.我希望一旦主文件关闭，第二个文件就会使用tkinter打开.这是 tkinter按钮的多个命令的延续

I have created 2 .py files. i want that once the primary file closes, the second one opens using tkinter. This is a continuation of multiple commands for a tkinter button .

我编写的退出按钮功能是:-

The exit button functionality I have written is:-

from Backup_Server import GUI_Interface

def close_func():
    os.kill(os.getpid(), signal.SIGINT)
    GUI_Interface()
    window.destroy()
    server_socket.close()

if __name__ == "__main__":
    exit_button = Button(topFrame, text='Quit', command=close_func)

GUI_Interface 是关闭现有 .py 文件后需要调用的函数.如果我将 GUI_Interface 用作 close_func()的第一个命令，那么它实际上不会退回到第二步，也永远不会关闭现有的 .py 文件.

GUI_Interface is a function that I need to call after closing the existing .py file. If I put GUI_Interface as the first command for close_func(), then it really does not go back to the 2nd step and never closes the existing .py file.

如果我将 GUI_Interface 放在最后，它只会关闭现有的一个，而永远不会打开新的 .py 文件的功能.

And if I place GUI_Interface in the end, it just closes the existing one and never opens the function of the new .py file.

-

尝试实现给定的解决方案，但它只是同时挂起了主Tkinter窗口和辅助Tkinter窗口:_

Tried implementing the given solution but it just hangs both the primary and secondary Tkinter window:_

  path_to_dir = os.getcwd()
  print("path of file:;:\n", path_to_dir)
  file_name = 'Backup_Server.py'  

  def close_func():
       os.system(f'cd "{path_to_dir}"')
       os.system(f'python {file_name}')
       exit()

  exit_button = Button(topFrame, text='Quit', command=close_func)

这是我根据给定的解决方案实现的.

This is what I implemented as per the solution given.

推荐答案

基本上，我已经能够通过创建另一个GUI_Interface线程并关闭现有文件来解决此问题.

So basically I have been able to solve this problem by creating another thread to GUI_Interface and then closing the existing file.

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