可可触控中的自定义键盘布局? [英] Custom keyboard layout in Cocoa Touch?

问题描述

我目前正在为iPhone开发BrainFuck解释器.看到BrainFuck只有八个命令，我想创建一个自定义的九按钮(八个命令+退格键)小键盘，而不是标准的iPhone键盘.有没有简单的方法可以做到这一点?

I am currently working on a BrainFuck interpreter for the iPhone. Seeing as BrainFuck only has eight commands, I want to create a custom nine-button (eight commands + backspace) keypad that will be showed instead of the standard iPhone keyboard. Is there any easy way of doing this?

谢谢，阿米特·罗恩-

推荐答案

据我所知，没有官方授权"的方法可以做到这一点.线程此处是很好地讨论了可以完成的各种方式.

As far as I can tell, there's no "officially authorized" way to do this. The thread here is a good discussion of a variety of ways it can be done.

此外，iPhone SDK协议明确禁止口译员.我不知道该规则的严格程度，因此请注意您的应用可能会被拒绝.

Also, the iPhone SDK agreement specifically forbids interpreters. I don't know how strictly that rule is kept, so be aware that your app may get rejected.

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