在网址中隐藏codeigniter控制器和方法名称 [英] Hide codeigniter both controller and method name from url
问题描述
我的网址是这样的: http://example.com/controller/method/param1/param2/param3/param4
我的目标是: http://example.com/param1/param2/param3/param4
在这里,我的控制器为"Home"和"Read".我还在底部包括了我的视图和路由配置.
Here my controllers 'Home' and 'Read'. I also include my view and route configuration at bottom.
<?php defined('BASEPATH') OR exit('No direct script access allowed');
class Home extends CI_Controller {
public function __construct()
{
parent::__construct();
}
/*
* Index method
*/
public function index() {
$this->db->select('a.*, c.*');
$this->db->join('category as c', 'c.catid=a.catid');
$this->db->limit(10);
$this->db->order_by('a.id', 'DESC');
$data['query'] = $this->db->get('article as a');
$this->load->view('header');
$this->load->view('home_view', $data);
$this->load->view('footer');
}
}
<?php defined('BASEPATH') OR exit('No direct script access allowed');
class Read extends CI_Controller {
public function __construct()
{
parent::__construct();
}
/*
* Index method
*/
public function index() {
$id = isset($this->uri->segment(3)) ? $this->uri->segment(3) : FALSE;
$this->db->select('a.*, c.*');
$this->db->join('category as c', 'c.catid=a.catid');
$this->db->where('p.id', $id);
$this->db->limit(1);
$data['query'] = $this->db->get('article as a');
$this->load->view('header');
$this->load->view('single_view', $data);
$this->load->view('footer');
}
}
home_view.php
home_view.php
请在下面查看锚点,这是我生成 http://example.com/param1/param2/param3/param4
Please take a look at anchor below, that was my goal to produce http://example.com/param1/param2/param3/param4
<div class="post-content">
<ul>
<?php foreach( $query->result() as $post ) : ?>
<li><a href="<?php echo site_url($post->term_name.'/'.$post->term_id.'/'.$post->id.'/'.strtolower(url_title($post->title))); ?>"><?php echo $post->title ?></a></li>
<?php endforeach; ?>
</ul>
</div>
当我定义控制器名称时,没问题.但是我不知道我的单个帖子的URL如何仅包含这四个参数
When I defined the controller name, it's no problem. But I can't figure out how my url for single post only contain those four params
<?php echo site_url('read/'.$post->term_name.'/'.$post->term_id.'/'.$post->id.'/'.strtolower(url_title($post->title))); ?>
在我的路由配置下面:
$route['(:any)'] = "read/index/$1";
任何帮助和建议将不胜感激.
Any help and advices will be appreciated.
最好的问候
推荐答案
检查可放置下一条路线的文档:
Checking the docs you can place next route:
$route['(:any)/(:any)/(:any)/(:any)'] = 'controller/method/$1/$2/$3/$4';
$route['(:any)/(:any)/(:any)'] = 'controller/method/$1/$2/$3';
$route['(:any)/(:any)'] = 'controller/method/$1/$2';
或者如果您要传递数字/整数
or if you are passing numbers/integers
$route['(:num)/(:num)/(:num)/(:num)'] = 'controller/method/$1/$2/$3/$4';
您也不要忘记将参数传递给您的方法,即使是FALSE也是如此.
You mustn't forget to pass arguments to your method as well, even as FALSE.
public function index($param1, $param2, $param3, $param4)
{
//rest of code that is using params
}
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