Google云端存储|PHP |上载的文件为0字节 [英] Google Cloud Storage | PHP | Uploaded files are at 0 Bytes
问题描述
我正在使用Codeigniter应用程序，并试图为用户提供上传文件的访问权限.服务器安装在运行CentOS 7和Apache 2的Google Compute Engine VM上，我试图使用Google Cloud Storage进行用户上传.目前，当我上传文件时，只有文件名被上传到GCS Bucket中，文件大小为0字节.
I am using a Codeigniter application and trying to provide access for users to upload files. the server is setup on a Google Compute Engine VM running CentOS 7 and Apache 2, I am trying to use Google Cloud Storage for user upload. Currently when I upload files only the file names are being uploaded into GCS Bucket with the file size as 0 bytes.
我的前端代码:
<body>
<form action="/includes/includes_gc/do_upload" class="dropzone" id="pfUploads" enctype="multipart/form-data">
</form>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.5.1/min/dropzone.min.js"></script>
<script>
Dropzone.options.pfUploads = {
paramName: "file",
uploadMultiple: true,
init: function () {
this.on('complete', function (data) {
console.log(data);
});
}
};
</script>
</body>
控制器功能:
public function do_upload() {
if ($_FILES) {
$filename = $_FILES['file']['name'];
$gs_name = file_get_contents($_FILES['file']['tmp_name']);
$bucketName = 'xxxxxx.appspot.com';
$kdir = dirname(getcwd(), 2);
$storage = new StorageClient([
'keyFile' => json_decode(file_get_contents($kdir . DIRECTORY_SEPARATOR . 'xxxxxx.json'), true),
'projectId' => 'xxxxxx'
]);
$file = fopen($gs_name, 'r');
$bucket = $storage->bucket($bucketName);
$bucket->upload($file, [
'name' => $filename
]);
$test = array();
array_push($test, basename($gs_name));
array_push($test, $bucketName);
array_push($test, $filename);
echo json_encode($test);
}
}
对于解决此问题，我将不胜感激.
I would appreciate any help to get this resolved.
在此先感谢.纳文(Naveen)
Thanks in Advance. Naveen
推荐答案
You’re assigning to the variable gs_name the return value of the function file_get_contents and you're passing that variable to the fopen function.
If there isn’t a path name which is the same as the contents of such file, which is normally expected, fopen returns the value false.
So you are passing the value false as a first parameter to $bucket->upload which effectively creates a blob of 0 bytes with the name you provided on the respective bucket.
因此，底线应该起作用:
So bottom line, the following should work:
public function do_upload() {
if ($_FILES) {
$filename = $_FILES['file']['name'];
$gs_name = $_FILES['file']['tmp_name'];
$file = file_get_contents($gs_name);
$bucketName = 'xxxxxx.appspot.com';
$kdir = dirname(getcwd(), 2);
$storage = new StorageClient([
'keyFile' => json_decode(file_get_contents($kdir . DIRECTORY_SEPARATOR . 'xxxxxx.json'), true),
'projectId' => 'xxxxxx'
]);
$bucket = $storage->bucket($bucketName);
$bucket->upload($file, [
'name' => $filename
]);
}
}
还请记住，您可以使用 upload 方法的返回值，例如:
Also keep in mind that you can use the return value of the upload method like:
$storage_object = $bucket->upload($file, ['name' => $filename]);
要进一步处理.
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