Java 8排序浮点值 [英] Java 8 sort float values

问题描述

我列出了有不同经历的员工，例如

I have a list of employees which had different experiences like

5.0、3.3、5.5、5.6、4.5等.

5.0,3.3,5.5,5.6,4.5 etc..

当我尝试通过使用 Math.round 对最大体验与最小体验进行排序时，给出的错误结果如下:

When I am trying to sort max to min experience by using Math.round it's giving the wrong result like:

5.6、5.0、5.5、5.3、4.5等.

5.6,5.0,5.5,5.3,4.5 etc..

我想要这样的结果:

5.6、5.5、5.3、5.0、4.5等.

5.6,5.5,5.3,5.0,4.5 etc..

在这里，我使用了 Collections.sort ，例如:

Here I used Collections.sort like:

Collections.sort(employeeList, new Comparator<Emp>() {
        @Override
        public int compare(Emp t, Emp t1) {
            return Math.round(t.getExperience() - t1.getExperience()); // which giving wrong results
//          return Float.compare(t.getExperience() - t1.getExperience()); // which is not working
        }
    });

此处 t1.getExperience()将为您提供浮动结果.

Here t1.getExperience() will give you float result.

推荐答案

Math.round(t.getExperience()-t1.getExperience())不比较两个数字，所以我不知道您期望达到什么.

Math.round(t.getExperience() - t1.getExperience()) doesn't compare the two numbers, so I don't know what you were expecting to achieve.

您应该使用:

Collections.sort(employeeList, new Comparator<Emp>() {
    @Override
    public int compare(Emp t, Emp t1) {
        return Float.compare(t1.getExperience(), t.getExperience());
    }
});

请注意，传递给 Float.compare 的参数与环绕式 compare 方法的参数相反，后者将按降序进行排序订单.

Note that the parameters passed to Float.compare are in the opposite order compared to the parameters of the wrapping compare method, which will produce sorting by descending order.

这篇关于Java 8排序浮点值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！