以编程方式确定要放置在图像上的最佳前景色 [英] Programmatically determine best foreground color to be placed onto an image

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本文介绍了以编程方式确定要放置在图像上的最佳前景色的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在开发一个节点模块,该模块将返回在背景图像上看起来最合适的颜色,当然该背景图像将具有多种颜色.

I'm working on a node module that will return the color that will look best onto a background image which of course will have multiple colors.

这是我到目前为止所拥有的:

Here's what I have so far:

'use strict';

var randomcolor = require('randomcolor');
var tinycolor = require('tinycolor2');

module.exports = function(colors, tries) {
  var topColor, data = {};

  if (typeof colors == 'string') { colors = [colors]; }
  if (!tries) { tries = 10000; }

  for (var t = 0; t < tries; t++) {
    var score = 0, color = randomcolor(); //tinycolor.random();

    for (var i = 0; i < colors.length; i++) {
      score += tinycolor.readability(colors[i], color);
    }

    data[color] = (score / colors.length);

    if (!topColor || data[color] > data[topColor]) {
      topColor = color;
    }
  }

  return tinycolor(topColor);
};

因此,它的工作方式是首先在此图像中为该脚本提供6种最主要的颜色:

So the way it works is first I provide this script with the 6 most dominant colors in an image like this:

[ { r: 44, g: 65, b: 54 },
  { r: 187, g: 196, b: 182 },
  { r: 68, g: 106, b: 124 },
  { r: 126, g: 145, b: 137 },
  { r: 147, g: 176, b: 169 },
  { r: 73, g: 138, b: 176 } ]

然后它将生成10,000种不同的随机颜色,然后选择具有6种给定颜色的平均对比度最高的颜色.

and then it will generate 10,000 different random colors and then pick the one that has the best average contrast ratio with the 6 given colors.

问题在于,取决于我使用哪种脚本生成随机颜色,无论给出的图像如何,我基本上都会得到相同的结果.

The problem is that depending on which script I use to generate the random colors, I'll basically get the same results regardless of the image given.

使用 tinycolor2 我总是会得到非常深的灰色(几乎黑色)或非常浅的灰色(几乎白色).使用 randomcolor ,我将得到深蓝色或浅桃红色.

With tinycolor2 I'll always end up with either a very dark gray (almost black) or a very light gray (almost white). And with randomcolor I'll either end up with a dark blue or a light peach color.

我的脚本可能不是解决此问题的最佳方法,但是有人有任何想法吗?

My script might not be the best way of going about this but does anybody have any ideas?

谢谢

推荐答案

找到显色.

提供的摘录显示了如何找到主要颜色的示例.它通过将图像分解为色相,饱和度和亮度分量来工作.

Finding dominant hue.

The provided snippet show an example of how to find a dominant colour. It works by breaking the image into its Hue, saturation and luminance components.

为加快处理速度,将图像缩小为较小的图像(在这种情况下为128 x 128像素).缩小过程的一部分还修剪了图像中的一些外部像素.

To speed up the process the image is reduced to a smaller image (in this case 128 by 128 pixels). Part of the reduction process also trims some of the outside pixels from the image.

const IMAGE_WORK_SIZE = 128;
const ICOUNT = IMAGE_WORK_SIZE * IMAGE_WORK_SIZE;
if(event.type === "load"){
    rImage = imageTools.createImage(IMAGE_WORK_SIZE, IMAGE_WORK_SIZE);  // reducing image
    c = rImage.ctx;
    // This is where you can crop the image. In this example I only look at the center of the image
    c.drawImage(this,-16,-16,IMAGE_WORK_SIZE + 32, IMAGE_WORK_SIZE + 32); // reduce image size

查找平均亮度

降低分辨率后,我将扫描像素,将其转换为hsl值,并获得平均亮度.

Find mean luminance

Once reduced I scan the pixels converting them to hsl values and get the mean luminance.

请注意,亮度是对数标度,因此平均值是平方和除以计数的平方根.

Note that luminance is a logarithmic scale so the mean is the square root of the sum of the squares divided by the count.

pixels = imageTools.getImageData(rImage).data;
l = 0;
for(i = 0; i < pixels.length; i += 4){ 
    hsl = imageTools.rgb2hsl(pixels[i],pixels[i + 1],pixels[i + 2]);
    l += hsl.l * hsl.l;
}
l = Math.sqrt(l/ICOUNT);

亮度和饱和度范围的色调直方图.

该代码可以找到在饱和度和亮度范围内的主要颜色.在该示例中,我仅使用一个范围,但是您可以根据需要使用任意数量的范围.仅使用在流明(亮度)和饱和(饱和度)范围内的像素.我为通过的像素记录了色调的直方图.

Hue histograms for luminance and saturation ranges.

The code can find the dominant colour in a range of saturation and luminance extents. In the example I only use one extent, but you can use as many as you wish. Only pixels that are inside the lum (luminance) and sat (saturation) ranges are used. I record a histogram of the hue for pixels that pass.

色相范围示例(之一)

hues = [{  // lum and sat have extent 0-100. high test is no inclusive hence high = 101 if you want the full range
        lum : {
            low :20,    // low limit lum >= this.lum.low
            high : 60,  // high limit lum < this.lum.high
            tot : 0,    // sum of lum values 
        },
        sat : { // all saturations from 0 to 100
            low : 0,
            high : 101,
            tot : 0, // sum of sat
        },
        count : 0, // count of pixels that passed
        histo : new Uint16Array(360), // hue histogram
    }]

在示例中,我使用平均亮度自动设置亮度范围.

In the example I use the mean Luminance to automatically set the lum range.

hues[0].lum.low = l - 30;
hues[0].lum.high = l + 30;

设置范围后,我将获得每个范围的色相直方图(在本例中为一个)

Once the range is set I get the hue histogram for each range (one in this case)

for(i = 0; i < pixels.length; i += 4){ 
    hsl = imageTools.rgb2hsl(pixels[i],pixels[i + 1],pixels[i + 2]);
    for(j = 0; j < hues.length; j ++){
        hr = hues[j]; // hue range
        if(hsl.l >= hr.lum.low && hsl.l < hr.lum.high){
            if(hsl.s >= hr.sat.low && hsl.s < hr.sat.high){
                hr.histo[hsl.h] += 1;
                hr.count += 1;
                hr.lum.tot += hsl.l * hsl.l;
                hr.sat.tot += hsl.s;
            }
        }
    }
}

从色调直方图中加权的平均色调.

然后使用直方图找到该范围的加权平均色调

Weighted mean hue from hue histogram.

Then using the histogram I find the weighted mean hue for the range

// get weighted hue for image
// just to simplify code hue 0 and 1 (reds) can combine
for(j = 0; j < hues.length; j += 1){
    hr = hues[j];
    wHue = 0;
    hueCount = 0;
    hr.histo[1] += hr.histo[0];
    for(i = 1; i < 360; i ++){
        wHue += (i) * hr.histo[i];
        hueCount += hr.histo[i];
    }
    h = Math.floor(wHue / hueCount);
    s = Math.floor(hr.sat.tot / hr.count);
    l = Math.floor(Math.sqrt(hr.lum.tot / hr.count));
    hr.rgb = imageTools.hsl2rgb(h,s,l);
    hr.rgba = imageTools.hex2RGBA(imageTools.rgba2Hex4(hr.rgb));
}

就是这样.剩下的只是展示和东西.上面的代码需要imageTools接口(已提供),该接口具有用于处理图像的工具.

And that is about it. The rest is just display and stuff. The above code requires the imageTools interface (provided) that has tools for manipulating images.

如何处理所发现的颜色取决于您.如果要补充色,只需将rgb转换为hsl imageTools.rgb2hsl ,然后将色相旋转180度,然后再转换回rgb.

What you do with the colour/s found is up to you. If you want the complementary colour just convert the rgb to hsl imageTools.rgb2hsl and rotate the hue 180 deg, then convert back to rgb.

var hsl = imageTools.rgb2hsl(rgb.r, rgb.g, rgb.b);
hsl.h += 180;
var complementRgb = imageTools.rgb2hsl(hsl.h, hsl.s, hsl.l);

就个人而言,只有一些颜色才能与它们的互补色很好地搭配.添加到货盘是有风险的,通过代码来做到这一点简直太疯狂了.坚持图片中的颜色.如果您想找到强调的颜色,请减小光度和饱和度范围.每个范围都会对找到的像素数进行计数,使用该计数可以使用关联的直方图中的颜色来找到像素的范围.

Personally only some colours work well with their complement. Adding to a pallet is risky, doing it via code is just crazy. Stick with colours in the image. Reduce the lum and sat range if you wish to find accented colours. Each range will have a count of the number of pixels found, use that to find the extent of pixels using the colors in the associated histogram.

该演示找到了围绕平均亮度的主要色调,并使用该色调以及平均饱和度和亮度创建了边框.

The demo finds the dominant hue around the mean luminance and uses that hue and mean saturation and luminance to create a border.

该演示使用了Wikipedia当天收集的图像中的图像,因为它们允许跨站点访问.

The demo using images from wikipedia's image of the day collection as they allow cross site access.

var images = [
   // "https://upload.wikimedia.org/wikipedia/commons/f/fe/Goldcrest_1.jpg",
   "https://upload.wikimedia.org/wikipedia/commons/thumb/2/22/Cistothorus_palustris_CT.jpg/450px-Cistothorus_palustris_CT.jpg",
    "https://upload.wikimedia.org/wikipedia/commons/thumb/3/37/Black-necked_Stilt_%28Himantopus_mexicanus%29%2C_Corte_Madera.jpg/362px-Black-necked_Stilt_%28Himantopus_mexicanus%29%2C_Corte_Madera.jpg",     
    "https://upload.wikimedia.org/wikipedia/commons/thumb/c/cc/Daurian_redstart_at_Daisen_Park_in_Osaka%2C_January_2016.jpg/573px-Daurian_redstart_at_Daisen_Park_in_Osaka%2C_January_2016.jpg",
    "https://upload.wikimedia.org/wikipedia/commons/thumb/d/da/Myioborus_torquatus_Santa_Elena.JPG/675px-Myioborus_torquatus_Santa_Elena.JPG",
    "https://upload.wikimedia.org/wikipedia/commons/thumb/e/ef/Great_tit_side-on.jpg/645px-Great_tit_side-on.jpg",
    "https://upload.wikimedia.org/wikipedia/commons/thumb/5/55/Sarcoramphus_papa_%28K%C3%B6nigsgeier_-_King_Vulture%29_-_Weltvogelpark_Walsrode_2013-01.jpg/675px-Sarcoramphus_papa_%28K%C3%B6nigsgeier_-_King_Vulture%29_-_Weltvogelpark_Walsrode_2013-01.jpg",,
    
];

function loadImageAddBorder(){
    if(images.length === 0){
        return ; // all done   
    }
    var imageSrc = images.shift();
    imageTools.loadImage(
        imageSrc,true,
        function(event){
            var pixels, topRGB, c, rImage, wImage, botRGB, grad, i, hsl, h, s, l, hues, hslMap, wHue, hueCount, j, hr, gradCols, border;
            const IMAGE_WORK_SIZE = 128;
            const ICOUNT = IMAGE_WORK_SIZE * IMAGE_WORK_SIZE;
            if(event.type === "load"){
                rImage = imageTools.createImage(IMAGE_WORK_SIZE, IMAGE_WORK_SIZE);  // reducing image
                c = rImage.ctx;
                // This is where you can crop the image. In this example I only look at the center of the image
                c.drawImage(this,-16,-16,IMAGE_WORK_SIZE + 32, IMAGE_WORK_SIZE + 32); // reduce image size
    
                pixels = imageTools.getImageData(rImage).data;
                h = 0;
                s = 0;
                l = 0;
                // these are the colour ranges you wish to look at
                hues = [{
                        lum : {
                            low :20,
                            high : 60,
                            tot : 0,
                        },
                        sat : { // all saturations
                            low : 0,
                            high : 101,
                            tot : 0,
                        },
                        count : 0,
                        histo : new Uint16Array(360),
                    }]
                for(i = 0; i < pixels.length; i += 4){ 
                    hsl = imageTools.rgb2hsl(pixels[i],pixels[i + 1],pixels[i + 2]);
                    l += hsl.l * hsl.l;
                }
                l = Math.sqrt(l/ICOUNT);
                hues[0].lum.low = l - 30;
                hues[0].lum.high = l + 30;
                for(i = 0; i < pixels.length; i += 4){ 
                    hsl = imageTools.rgb2hsl(pixels[i], pixels[i + 1], pixels[i + 2]);
                    for(j = 0; j < hues.length; j ++){
                        hr = hues[j]; // hue range
                        if(hsl.l >= hr.lum.low && hsl.l < hr.lum.high){
                            if(hsl.s >= hr.sat.low && hsl.s < hr.sat.high){
                                hr.histo[hsl.h] += 1;
                                hr.count += 1;
                                hr.lum.tot += hsl.l * hsl.l;
                                hr.sat.tot += hsl.s;
                            }
                        }
                    }
                }
                // get weighted hue for image
                // just to simplify code hue 0 and 1 (reds) can combine
                for(j = 0; j < hues.length; j += 1){
                    hr = hues[j];
                    wHue = 0;
                    hueCount = 0;
                    hr.histo[1] += hr.histo[0];
                    for(i = 1; i < 360; i ++){
                        wHue += (i) * hr.histo[i];
                        hueCount += hr.histo[i];
                    }
                    h = Math.floor(wHue / hueCount);
                    s = Math.floor(hr.sat.tot / hr.count);
                    l = Math.floor(Math.sqrt(hr.lum.tot / hr.count));
                    hr.rgb = imageTools.hsl2rgb(h,s,l);
                    hr.rgba = imageTools.hex2RGBA(imageTools.rgba2Hex4(hr.rgb));
                }
                gradCols = hues.map(h=>h.rgba);
                if(gradCols.length === 1){
                    gradCols.push(gradCols[0]); // this is a quick fix if only one colour the gradient needs more than one
                }
                border = Math.floor(Math.min(this.width / 10,this.height / 10, 64));
    
                wImage = imageTools.padImage(this,border,border);
                wImage.ctx.fillStyle = imageTools.createGradient(
                    c, "linear", 0, 0, 0, wImage.height,gradCols
                );
                wImage.ctx.fillRect(0, 0, wImage.width, wImage.height);
                wImage.ctx.fillStyle = "black";
                wImage.ctx.fillRect(border - 2, border - 2, wImage.width - border * 2 + 4, wImage.height - border * 2 + 4);           
                wImage.ctx.drawImage(this,border,border);
                wImage.style.width = (innerWidth -64) + "px";
                document.body.appendChild(wImage);
                setTimeout(loadImageAddBorder,1000);
            }
        }
        
    )
}

setTimeout(loadImageAddBorder,0);



/** ImageTools.js begin **/
var imageTools = (function () {
    // This interface is as is. 
    // No warenties no garenties, and 
    /*****************************/
    /* NOT to be used comercialy */
    /*****************************/
    var workImg,workImg1,keep; // for internal use
    keep = false; 
    const toHex = v => (v < 0x10 ? "0" : "") + Math.floor(v).toString(16);
    var tools = {
        canvas(width, height) {  // create a blank image (canvas)
            var c = document.createElement("canvas");
            c.width = width;
            c.height = height;
            return c;
        },
        createImage (width, height) {
            var i = this.canvas(width, height);
            i.ctx = i.getContext("2d");
            return i;
        },
        loadImage (url, crossSite, cb) { // cb is calback. Check first argument for status
            var i = new Image();
            if(crossSite){
                i.setAttribute('crossOrigin', 'anonymous');
            }
            i.src = url;
            i.addEventListener('load', cb);
            i.addEventListener('error', cb);
            return i;
        },
        image2Canvas(img) {
            var i = this.canvas(img.width, img.height);
            i.ctx = i.getContext("2d");
            i.ctx.drawImage(img, 0, 0);
            return i;
        },
        rgb2hsl(r,g,b){ // integers in the range 0-255
            var min, max, dif, h, l, s;
            h = l = s = 0;
            r /= 255;  // normalize channels
            g /= 255;
            b /= 255;
            min = Math.min(r, g, b);
            max = Math.max(r, g, b);
            if(min === max){  // no colour so early exit
                return {
                    h, s,
                    l : Math.floor(min * 100),  // Note there is loss in this conversion
                }
            }
            dif = max - min;
            l = (max + min) / 2;
            if (l > 0.5) { s = dif / (2 - max - min) }
            else { s = dif / (max + min) }
            if (max === r) {
                if (g < b) { h = (g - b) / dif + 6.0 }
                else { h = (g - b) / dif }                   
            } else if(max === g) { h = (b - r) / dif + 2.0 }
            else {h = (r - g) / dif + 4.0 }   
            h = Math.floor(h * 60);
            s = Math.floor(s * 100);
            l = Math.floor(l * 100);
            return {h, s, l};
        },
        hsl2rgb (h, s, l) { // h in range integer 0-360 (cyclic) and s,l 0-100 both integers
            var p, q;
            const hue2Channel = (h) => {
                h = h < 0.0 ? h + 1 : h > 1 ? h - 1 : h;
                if (h < 1 / 6) { return p + (q - p) * 6 * h }
                if (h < 1 / 2) { return q }
                if (h < 2 / 3) { return p + (q - p) * (2 / 3 - h) * 6 }
                return p;        
            }
            s = Math.floor(s)/100;
            l = Math.floor(l)/100;
            if (s <= 0){  // no colour
                return {
                    r : Math.floor(l * 255),
                    g : Math.floor(l * 255),
                    b : Math.floor(l * 255),
                }
            }
            h = (((Math.floor(h) % 360) + 360) % 360) / 360; // normalize
            if (l < 1 / 2) { q = l * (1 + s) } 
            else { q = l + s - l * s }
            p = 2 * l - q;        
            return {
                r : Math.floor(hue2Channel(h + 1 / 3) * 255),
                g : Math.floor(hue2Channel(h)         * 255),
                b : Math.floor(hue2Channel(h - 1 / 3) * 255),
            }    
            
        },        
        rgba2Hex4(r,g,b,a=255){
            if(typeof r === "object"){
                g = r.g;
                b = r.b;
                a = r.a !== undefined ? r.a : a;
                r = r.r;
            }
            return `#${toHex(r)}${toHex(g)}${toHex(b)}${toHex(a)}`; 
        },
        hex2RGBA(hex){ // Not CSS colour as can have extra 2 or 1 chars for alpha
                                  // #FFFF & #FFFFFFFF last F and FF are the alpha range 0-F & 00-FF
            if(typeof hex === "string"){
                var str = "rgba(";
                if(hex.length === 4 || hex.length === 5){
                    str += (parseInt(hex.substr(1,1),16) * 16) + ",";
                    str += (parseInt(hex.substr(2,1),16) * 16) + ",";
                    str += (parseInt(hex.substr(3,1),16) * 16) + ",";
                    if(hex.length === 5){
                        str += (parseInt(hex.substr(4,1),16) / 16);
                    }else{
                        str += "1";
                    }
                    return str + ")";
                }
                if(hex.length === 7 || hex.length === 9){
                    str += parseInt(hex.substr(1,2),16) + ",";
                    str += parseInt(hex.substr(3,2),16) + ",";
                    str += parseInt(hex.substr(5,2),16) + ",";
                    if(hex.length === 9){
                        str += (parseInt(hex.substr(7,2),16) / 255).toFixed(3);
                    }else{
                        str += "1";
                    }
                    return str + ")";                
                }
                return "rgba(0,0,0,0)";
            }
            
                
        },            
        createGradient(ctx, type, x, y, xx, yy, colours){ // Colours MUST be array of hex colours NOT CSS colours
                                                          // See this.hex2RGBA for details of format
            var i,g,c;
            var len = colours.length;
            if(type.toLowerCase() === "linear"){
                g = ctx.createLinearGradient(x,y,xx,yy);
            }else{
                g = ctx.createRadialGradient(x,y,xx,x,y,yy);
            }
            for(i = 0; i < len; i++){
                c = colours[i];
                if(typeof c === "string"){
                    if(c[0] === "#"){
                        c = this.hex2RGBA(c);
                    }
                    g.addColorStop(Math.min(1,i / (len -1)),c); // need to clamp top to 1 due to floating point errors causes addColorStop to throw rangeError when number over 1
                }
            }
            return g;
        },
        padImage(img,amount){
            var image = this.canvas(img.width + amount * 2, img.height + amount * 2);
            image.ctx = image.getContext("2d");
            image.ctx.drawImage(img, amount, amount);
            return image;
        },
        getImageData(image, w = image.width, h = image.height) {  // cut down version to prevent intergration 
            if(image.ctx && image.ctx.imageData){
                return image.ctx.imageData;
            }
            return (image.ctx || (this.image2Canvas(image).ctx)).getImageData(0, 0, w, h);
        },
    };
    return tools;
})();

/** ImageTools.js end **/

这篇关于以编程方式确定要放置在图像上的最佳前景色的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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