壳牌和||在python中 [英] shell's && and || in python

问题描述

在shell中，如果我只想在第一个命令成功的情况下执行第二个命令，我就会这样做

In shell if I want to execute a second command only if the first command was successful I would do this

cmd1 && cmd2

如果第一个命令失败，我需要执行第二个命令，我会这样做

And if I need to execute the second command if the first fails I would do this

cmd1 || cmd2

我正在通过python脚本中的subprocess.call调用命令列表.我该怎么做?

I'm calling a list of commands via subprocess.call in a python script. How can I do the above?

推荐答案

将 shell = True 传递给 subprocess.call ，您可以执行任意shell命令.只要确保您正确转义/引用所有内容.

Pass shell=True to subprocess.call and you can execute arbitrary shell commands. Just make sure you escape/quote everything correctly.

subprocess.call("true && echo yes!", shell=True)

打印是！，而

subprocess.call("false && echo yes!", shell=True)

不打印任何内容.

(您无需转义或引用&& 或 || ，但其中带有空格的文件名可能会很麻烦.)

(You don't need to escape or quote && or ||, but filenames with spaces in them can be a pain.)

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