源代码缺少函数体，如何编译? [英] Source missing function body, how is it compiling?

问题描述

在Go lang源代码中，我看到一个声明的函数，没有任何主体. https://github.com/golang/go/blob/master/src/math/log10.go#L9

In the Go lang source code, I see a function declared without any body. https://github.com/golang/go/blob/master/src/math/log10.go#L9

func Log10(x float64) float64

但是当我执行相同操作时，它给我一个错误:____缺少函数体

But when I do the same it gives me an error: missing function body for __

https://play.golang.org/p/Ncp-0-8vHB

这在Go源代码中如何工作?我的意思是数学软件包如何编译?此源文件仅用于文档目的吗?

How is this working in the Go source code? I mean how is the math package compiling? Is this source file just for documentation purposes?

Log10似乎是log10的公开/公开版本，但是没有"getter"约定或该语言中的类似内容，因此Log10的主体在哪里声明??

It seems like Log10 is a public/exposed version of log10, but there is no "getter" convention or anything like that in the language, so where is the body of Log10 declared???

推荐答案

它是在同一程序包的 *.s 文件中为各种体系结构在程序集中定义的.

It is defined in assembly for various architectures in the *.s files located in the same package.

每个规范:

函数声明可以省略主体.这样的声明为Go外部实现的功能(例如汇编例程)提供了签名.

A function declaration may omit the body. Such a declaration provides the signature for a function implemented outside Go, such as an assembly routine.

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